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nataly862011 [7]
3 years ago
11

Which has the least absolute value?A. 5B. 30C. -10D. -50

Mathematics
2 answers:
ziro4ka [17]3 years ago
7 0
Absolute value means the total distance from zero. So you get rid of any negative signs and then look at which number has the lowest value (which is the smallest number without any negative signs).
stellarik [79]3 years ago
3 0
Hello, 

we know that:  |a|=a \\ |-a|=a

Then refgardless of the sign, the smallest number will have the least absolute value. 

Answer: A
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Jet001 [13]
An item that costs $205000, when discounted 15 percent, will cost $174250. The easiest way of calculating discount is, in this case, to multiply the normal price $205000 by 15 then divide it by one hundred. So, the discount is equal to $30750. To calculate the sales price, simply deduct the discount of $30750 from the original price $205000 then get $174250 as the sales price. which mean is C
3 0
2 years ago
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Solve the equation 3/4x+3-2x = -1/4+1/2x+5
elena55 [62]
Hi there! The answer is x = -1

Let's solve this equation step by step!
\frac{3}{4} x + 3 - 2x = - \frac{1}{4} + \frac{1}{2} x + 5

First collect terms.
- 1 \frac{1}{4} x + 3 = \frac{1}{2} x + 4 \frac{3}{4}

Subtract (1/2)x from both sides.
- 1\frac{3}{4} x + 3 = 4 \frac{3}{4}

Subtract 3 from both sides.
- 1\frac{3}{4} x = 1 \frac{3}{4}

And finally divide by -1 3/4
x = \frac{7}{4} \div - \frac{7}{4} = \frac{7}{4} \times - \frac{4}{7} = - \frac{28}{28} = - 1
8 0
3 years ago
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7a-4=3(a+9)+4a plz help
sweet [91]
7a-4=3a+27+4a
7a-4=7a+27

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7 0
2 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
2 years ago
How o I get the awnser to 9s+3=57 I need help asap im in 8th grade
PIT_PIT [208]
First subtract 3 from both sides of the equal sign. 
9s + 3 = 57
      - 3     -3
9s = 54

Then divide both sides by 9.
9s = 54
/9     /9
s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6  + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations. 
3 0
3 years ago
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