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Ugo [173]
3 years ago
5

2. What is an expression for the distance between the origin and a point P(x, y)?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Step-by-step explanation:

Using distance formula: { origin is (0,0)}

√(x - 0)² + (y - 0)²

√x² + y²

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Line AB contains points A (0,0) and B (2, 2). Line CD contains points C (3, 1) and D (5,3).
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I think they would be parallel, because if you put points A,B,C,D into Desmos they come up to look parallel. hope this helps :)
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Emma and Clair are planning to sell lemonade on their street. They have two recipes to choose from. Emma’s recipe calls for the
gregori [183]

Answer:

Emma's recipe will be more lemony because

5/2=2.5

2/1=2

Step-by-step explanation:

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Dylan makes $1500 a month plus $200 for every car he sales
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3 years ago
The sum of three consecutive integers is 165. What are the integers?<br> The first integer is
Dovator [93]

Answer:

x = 54

Step-by-step explanation:

Let the 3 consecutive integers be,

→ x, x + 1, x + 2

Then the equation is,

→ (x) + (x + 1) + (x + 2) = 165

The required value of x will be,

→ (x) + (x + 1) + (x + 2) = 165

→ 3x + 3 = 165

→ 3x = 165 - 3

→ x = 162/3

→ [ x = 54 ]

Hence, the first integer is 54.

4 0
1 year ago
Julian’s friend James also has a tank in the shape of a triangular prism. The dimensions of James’ tank are each exactly 2 3/4 t
malfutka [58]

The approximate area of the triangular base of James’ tank is 3025 in²

To find the approximate area of the triangular base of James' tank, we need to know what scale is.

<h3>What is scale?</h3>

A scale is the ratio of two dimension. It is given by scale = New dimension/old dimension

Given that the dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank.

The scale of the area of James' tank to the area of triangular base of Julian's tank is S = (2³/₄)²

= (11/4)²

= 121/16

Let

  • A = area of triangular base of James' tank,
  • A' = area of triangular base of Julian's tank = 400 in²

So, scale, S = A/A'

<h3>The approximate area of the triangular base of James’ tank</h3>

So, making A subject of the formula, we have

A = SA'

A = 121/16 × 400 in²

A = 121 × 25 in²

A = 3025 in²

So, the approximate area of the triangular base of James’ tank is 3025 in²

Learn more about area of triangle here:

brainly.com/question/27436493

#SPJ1

5 0
3 years ago
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