Answer:
Eve is employing a <u>chosen-ciphertext attack.</u>
Explanation:
Encryption is a strategy employed in the cyber world to allow sensitive and private data to be unreadable in the form of text or make the content of the data inaccessible by intruders. This is imperative to guard data and can only be accessed with the use of a key (password). Whoever has the authorized key could get access to the data thereby making the encrypted data readable in the process called Decryption.
The Ciphertext is a term used to explain data encrypted in the form of text.
When Eve tricked Alice into decrypting a bunch of ciphertexts, she was interested in having the general public key or private key depending on what she wants to get access to which makes it a chosen-ciphertext attack. Usually, these keys are in algorithm formats with long characters. When the chosen-ciphertext is analyzed by Eve, then she could guess the user secret key.
Answer:
i think it is c. whatever that is.
Explanation:
because its not any of those. D. is exceptional tho
hope this helps! :)
Answer:
<em>import java.util.Scanner;</em>
<em>public class ANot {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner(System.in);</em>
<em> System.out.println("Please enter a string of words");</em>
<em> String n = in.nextLine();</em>
<em> int count = 0;</em>
<em> for (int i=0; i<n.length(); i++){</em>
<em> if((n.charAt(i) != '.') &&(n.charAt(i) != ',') && (n.charAt(i) != ' ')){</em>
<em> count++;</em>
<em> }</em>
<em> }</em>
<em> System.out.println(count);</em>
<em> }</em>
<em>}</em>
Explanation:
- Prompt User to input the string and assign to a variable
- SET count =0.
- Using a for loop iterate over the string
- if((n.charAt(i) != '.') &&(n.charAt(i) != ',') && (n.charAt(i) != ' ')) then count =count +1.
- PRINT count.
