The <span>magnitude of the largest positive value you can place in a bool, a char, an int, a float, a double are as follows:
</span><span>Int: 4 bytes Float: 4 double: 8 char: 1 boolean: 1
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
Duplicate these displays.
Explanation:
<u>A. Show only on 1</u> <em>displays only the first screen and disconnects the second one</em>
<u>B. Extend these displays</u> <em>displays two different outputs on the same computer</em>
<u>C. Show only on 2.</u> <em>displays only the second screen and disconnects the first one</em>
<u>D. Duplicate these displays.</u> <em>displays the same output for both screen</em>
A Deceleration device.
A rope, wire rope, or strap with connectors at each end for connecting the 5 point body harness to a lifeline, or anchorage.
Look under OSHA Flashcards on Quizlet and..
OSHA: Fall Protection in Construction, Subpart M and just past that area in the document.
This is from that document on page 13 and 14:
Fall Restraint Systems: While fall restraint systems are not
mentioned in Subpart M, OSHA
recognizes a fall restraint system as
a means of prevention. The system,
if properly used, tethers a worker
in a manner that will not allow a
fall of any distance. This system is
comprised of a body belt or body
harness, an anchorage, connectors,
and other necessary equipment.
Other components typically include
Photo: Skip Pennington
OCCUPATIONAL SAFETY AND HEALTH ADMINISTRATION
1 4
a lanyard, a lifeline, and other devices. For a restraint system
to work, the anchorage must be strong enough to prevent the
worker from moving past the point where the system is fully
extended, including an appropriate safety factor.
*In a November 2, 1995 interpretation letter to Mr. Dennis
Gilmore, OSHA suggested that, at a minimum, a fall restraint
system must have the capacity to withstand at least 3,000
pounds or twice the maximum expected force that is needed
to restrain the person from exposure to the fall hazard. In
determining this force, consideration should be given to
site-specific factors such as the force generated by a person
(including his/her tools, equipment, and materials) walking,
slipping, tripping, leaning, or sliding along the work surface.
Answer:
def newton(n):
#Define the variables.
t = 0.000001
esti = 1.0
#Calculate the square root
#using newton method.
while True:
esti = (esti + n / esti) / 2
dif = abs(n - esti ** 2)
if dif <= t:
break
#Return the result.
return esti
#Define the main function.
def main():
#Continue until user press enters.
while True:
try:
#Prompt the user for input.
n = int(input("Enter a number (Press Enter to stop):"))
#display the results.
print("newton = %0.15f" % newton(n))
except:
return
#Call the main function.
main()
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