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professor190 [17]
3 years ago
12

Write down the complement 17,30​

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Be QuItE  pEaSaNt!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Maria has a collection of 40 baseball cards, of which x cards are damaged. The value of each undamaged card is 5 dollars and the
hodyreva [135]

(40 - x) represents A. the number of undamaged cards

Step-by-step explanation:

Step 1; Maria has a total of 40 cards out of which x number of cards are damaged so 40 - x cards are undamaged. The value of an undamaged card is 5 dollars whereas every damaged card has a value of 3 dollars.

Step 2; We need to determine what each term in equation 5(40−x)+3x represents. The equation will give us how much total value Maria's card collection has.

The first term 5 (40 - x) signifies the total value of the undamaged cards in the deck where (40 - x) equals the total number of undamaged cards.

The second term represents the total value of the undamaged cards.

So the second factor of the first term i.e (40 - x) represents the amount of undamaged cards in her collection.

7 0
3 years ago
A. x=51, y=63<br>b. x=77, y=63<br>c x=63, y=77<br>d x=77, y=65
vekshin1
The answer is b. x=77, y=63
5 0
3 years ago
Read 2 more answers
Please answer my questions!
timama [110]

Answer:

What is the question.

Step-by-step explanation:

Cant help u without one.

4 0
3 years ago
What is the axis of symmetry
zavuch27 [327]
The graph of a quadratic function is a parabola. The axis of symmetry<span> of a parabola is a vertical line that divides the parabola into two congruent halves. The </span>axis of symmetry<span>always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the </span>axis of symmetry<span> of the parabola.</span>
3 0
3 years ago
Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).
Korolek [52]

Answer:

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y  = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y  = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y  = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

6 0
3 years ago
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