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sergey [27]
3 years ago
14

The College Board states that the average math SAT score is 514 with a standard deviation of 117. Colleen gathered data from 50

students in her graduating class and found the average score to be 523. She thinks that her class’s math SAT score is different from the average. Which of the following are the correct null hypothesis and alternate hypothesis?
Mathematics
2 answers:
ratelena [41]3 years ago
7 0
In hypothesis testing, A null hypothesis (H0) is a claim which the person conducting the research wants to test while an alternative hypothesis (H1) is a contradiction of the null hypothesis.

There are two types of tests in hypothesis testing.

One tailed test: In one tailed test, a claim that a parameter is greater than/ less than a value is being tested. i.e mean > value or mean < value.

Two tailed test: In a two tailed test, a claim that a value is equal to a value is tested, i.e mean = value.

In the question above, Colleen is testing the claim that the average score of her class is the same as others against that it is different from others.
Therefore, the null hypothesis is H0: mean = 514 while the alternative hypothesis is H1: mean ≠ 514
kherson [118]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Explain how place value could be used to find the difference of 4.23 and 2.75
seropon [69]
You can use place value to align the numbers together so you can subtract correctly. Match the ones, tenths, and hundredths digits together to subtract.

4.23
2.75

then you can subtract correctly without any mistakes in place value
6 0
3 years ago
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1
lana [24]

We assume that the function is as follows:

f^{-1_{}}(2)=?

Then, we have that:

f^{-1}(x)=\frac{1}{f(x)}

Thus, if we have that:

f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}

Therefore, the value for the function is f^-1(2) = -1/2 or

f^{-1}(2)=-\frac{1}{2}

8 0
1 year ago
No step by step answers or links
inysia [295]

Answer:

1. k = 15

2. d = 20

3. n = 3

6 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
4 years ago
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