Answer:
Part a) The distance on a map between Joseph's house and the airport is 2.53 inches
Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches
Step-by-step explanation:
Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles
Let
x-----> the distance on a map
1/9.5=x/24
x=24/9.5=2.53 inches
Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between airport to the restaurant is 16 miles
Let
x-----> the distance on a map
1/9.5=x/16
x=16/9.5=1.68 inches
The total distance on a map between Joseph's house and the restaurant is equal to
2.53 inches+1.68 inches=4.21 inches
Answer:
is the 5.2% per hour or for the whole 25 hours?
Need to know in order to solve the question
Step-by-step explanation:
G(X)=6X-3
Y=6X-3
X=6Y-3
X+3=6Y
Y=(X+3)/6
G^-1(9)=(X+3)/6
G^-1(9)=(9+3)/6
G^-1(9)=2
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36
B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B
distance between 2 points x and y is |x-y|
so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
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