Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
10.9 = x% of 34
10.9 is the amount
x% is the percent
34 is the base
Answer:
Step-by-step explanation:
Answer:
-6
Step-by-step explanation:
4.8(x)+1.2(y)=2.4
9.6 + 1.2y = 2.4
subtract 9.6 from both sides
1.2y = - 7.2
divide by 1.2 on both sides
y = -6
I think this is your question right????
