Which number is irrational?

Mathematics

1 answer:

arsen [322]3 years ago

7 0

Answer: pie, the last one

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To the Nearest ten-thousand, I round to 80,000. I round to 81,000 when rounded to the nearest thousand, and to 81, 220. I am a p

Amiraneli [1.4K]

Either 2,666 or 2,722
Hope this helped :)

3 0

3 years ago

Read 2 more answers

(10 points) Can someone help me solve this please

jenyasd209 [6]

Answer:

y = -3/2x - 13 and y = 4/5x - 4/5

Step-by-step explanation:

I suppose those are 2 opposite equations, and I will solve both, assuming you need both solved.

1) y = -3/2x - 13

2) y = 4/5x - 4/5

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3 years ago

Write the equation of the line that is perpendicular to the line y=-6x+4 and goes through the point (12,-3)

Vladimir79 [104]

Perpendicular angle so the slope is the opposite reciprocal: 1/6

$y = \frac{1}{6} + b$
plug in x and y values of given point
$- 3 = \frac{1}{6} (12) + b$
find b
b = - 5

rewrite equation with b and slope values
$y = \frac{1}{6} x - 5$

5 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$