<span>The number of dollars collected can be modelled by both a linear model and an exponential model.
To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8)
The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3
y - 2 = 3(x - 1) = 3x - 3
y = 3x - 3 + 2 = 3x - 1
Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17
To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2.
8 = 2r^(3 - 1) = 2r^2
r^2 = 8/2 = 4
r = sqrt(4) = 2
Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
Answer:
P= 150
Substitute P with 150 and you will get 30
Answer:
Y= -4X + 8
Step-by-step explanation:
Use rise/run to find slope (y2- y1/ x2-x1). Plug the slope into point-slope form [y-y1= m(x-x1)]. this is your answer
Answer:
The correct option is;
C. 52.2 × 4.4 × 2 + 47.8 × 4.4 × 2
Step-by-step explanation:
The area of the square frame is the area of the inner square subtracted from the area of the outer square
Which gives;
52.2² - 47.8² = 440
Therefore;
Option A. 52.2² - 47.8² is a correct way of finding the area of the square frame
Option B. 2 × ((52.2×2.2) + (47.8×2.2)) = 440, is a correct way of finding the area of the square frame
Option C. 52.2 × 4.4 × 2 + 47.8 × 4.4 × 2 = 880, is not a correct way of finding the area of the square frame
The error is the thickness is 2.2 not 4.4
Option D. 100×(52.2 - 47.8) = (52.2 + 47.8) × (52.2 - 47.8) = 52.2² - 47.8² = 440, is a correct way of finding the area of the square frame
