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2 years ago

Someone please help meeeee

Mathematics

2 answers:

vladimir1956 [14]2 years ago

7 0

Answer: decrease

Step-by-step explanation:

kvv77 [185]2 years ago

3 0

Decrease because the arrow is pointing down

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PLEASE HELP!! Factor 6x^2-42x-54 Please show work!

skad [1K]

first, rewrite 54 as 6•9

next, rewrite 42 as 6•7

then, that gets you 6x^2 -6•7x- 6•9

lastly, factor out the common term (6)

and then you get 6(x^2-7x-9)

please mark as brainliet <3

6 0

2 years ago

Can someone solve this?

noname [10]

Answer:

$\frac{5}{6}$ , $\frac{5}{6}$ , and "Yes"

Step-by-step explanation:

We will do as the instructions say.

-> See attached.

5 0

2 years ago

In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

olya-2409 [2.1K]

Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

8 0

3 years ago

At EHS, a football player ran a total of 1,032 yards in 12 games. If the rate stays the

nata0808 [166]

I think it would be 1462 yards

3 0

2 years ago

a proportional relationship is represented on a graph with a line that had a slope of 65. what is the unit rate of the relations

erik [133]

Answer:

Step-by-step explanation:

8 0

3 years ago