If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
Answer:
Step-by-step explanation:
Similar triangles
Cross multiply
2*(x+2) = 3*x
2x + 2*2 = 3x
2x + 4 = 3x
Subtract 2x from both sides
2x + 4 -2x = 3x - 2x
4 = x
x = 4
Answer:
Step-by-step explanation:
(2y²)³=2³×y^6=8y^6
=8×y×y×y×y×y×y