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3 years ago

Write and solve an equation to find the value of x. Show your work.

Mathematics

1 answer:

brilliants [131]3 years ago

8 0

Answer:

x = 9

Step-by-step explanation:

(13x + 2) + (5x -7 ) + (3x-4) = 180°( sum of angles in a triangle)

13x + 2 + 5x - 7 + 3x - 4 = 180

13x + 5x +3x + 2 - 7 - 4 = 180

21x - 9 = 180

add 9 to both sides

21x - 9 + 9 = 180 + 9

21x = 189

Divide through by 21

x = 9

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X is greater than or equal to -2

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3 years ago

Which is equivalent to sin-1(–0.4)? Round your answer to the nearest hundredth of a radian.

strojnjashka [21]

Answer:

-0.41 radians

Step-by-step explanation

(Credit goes to calculista)

let

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using a calculator

A=-23.578°----> the angle A belong to the IV quadrant

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4 0

3 years ago

A sector of a circle has a central angle measuring 15 degrees and the radius of the circle measures 9 inches. What is the arc le

Kamila [148]

Answer:

Arc length is $\dfrac{3\pi }{4}\ \text{inches}$

Step-by-step explanation:

We have,

Central angle is 15 degrees and the radius of the circle measures 9 inches.

It is required to find the arc length of the sector.

The relation between arc length and the central angle is given by :

$\dfrac{\text{arc length}}{\text{circumference}}=\dfrac{\theta}{360}$

Circumference, $C=2\pi r=18\pi$

$\theta=15^{\circ}$

$\dfrac{x}{18\pi }=\dfrac{15}{360}\\\\\dfrac{x}{18\pi }=\dfrac{1}{24}\\\\x=\dfrac{18\pi }{24}\\\\x=\dfrac{3\pi }{4}\ \text{inches}$

Hence, the correct option is (b).

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3 years ago

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Step-by-step explanation:

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2 years ago

What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?

Readme [11.4K]

Answer:

The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

Step-by-step explanation:

If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.

From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).

If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.

Midpoint formula.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Midpoint of DF,

$Midpoint=(\frac{1-3}{2},\frac{4+3}{2})$

$Midpoint=(-1,3.5)$

Midpoint of EF,

$Midpoint=(\frac{1-3}{2},\frac{1+3}{2})$

$Midpoint=(-1,2)$

Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

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3 years ago