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Alborosie
3 years ago
10

What is the slope of G(-11,-3) and H(-6,7)

Mathematics
1 answer:
Gwar [14]3 years ago
8 0
(-11,-3) (-6,7)
7+3/-6+11= 10/-5
Slope is -2
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Step-by-step explanation:

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Step by Step

This is probably the most difficult problem in elementary Geometry. I stopped counting after about 20 steps. The trick is to follow a very carefully constructed diagram which looks simple enough until you start using it.


Givens

  • Triangle ABC with 2 equal sides AB and AC.
  • BC is the third side and is not equal to either of the other 2.

3 0
4 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
Y_Kistochka [10]
Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}) }  \\  =  \sqrt{( {(3- 1)}^{2}  +  {(6 - 2)}^{2} )}  \\  =  \sqrt{( {2}^{2}  +  {4}^{2} )}  =  \sqrt{(4 + 16)} \\  =  \sqrt{20} = 2 \sqrt{5}  = 4.47
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4 0
3 years ago
Read 2 more answers
Write an equation in standard form of the line that passes through the point (9, 2) with a slope of 1/3
Elan Coil [88]

Answer:

y=1/3x-1

Step-by-step explanation:

You want to find the equation for a line that passes through the point (9,2) and has a slope of 1/3.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 1/3. So you can right away fill in the equation for a line somewhat to read:

y=1/3x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(9,2). When x of the line is 9, y of the line must be 2.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 1/3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (9,2).

So, why not plug in for x the number 9 and for y the number 2? This will allow us to solve for b for the particular line that passes through the point you gave!.

(9,2). y=mx+b or 2=1/3 × 9+b, or solving for b: b=2-(1/3)(9). b=-1.

The equation of the line that passes through the point (9,2) with a slope of 1/3

is

y=1/3x-1

4 0
3 years ago
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