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1 year ago

Complete the remainder of the

Mathematics

1 answer:

N76 [4]1 year ago

8 0

Answer: 2, 4, 6, 8

Step-by-step explanation:

Just plug x into the equation for each one.

x = -3

$y=\frac{2(-3)}{3} +4\\y=\frac{-6}{3} +4\\y=2$

With this one, you can see it is a linear equation and for every increase of 3 on x, y in increased by 2.

x -6 -3 0 3 6

y 0 2 4 6 8

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WILL MARK BRAINLIEST IF CORRECT

Mrrafil [7]

Answer: C

Step-by-step explanation:

The x times 4 equals the y in each column.

4 0

2 years ago

Read 2 more answers

What is the equation of this line in standard form? 8x−7y=−25 8x−9y=23 8x−9y=−23 9x−8y=23 Number graph ranging from negative fiv

Gnoma [55]

Answer:

The equation of line is:

$8x-9y=-23$

Step-by-step explanation:

We are given that a graph is a that passes through two points:

$(-4,-1)$ and $(\dfrac{1}{2},3)$

We know that the equation of line passing through two points:

$(a,b)$ and $(c,d)$ is given by:

$y-b=\dfrac{d-b}{b-a}\times (x-a)$

Here we have:

$(a,b)=(-4,-1)$ and $(c,d)=(\dfrac{1}{2},3)$

Hence, the equation of line is:

$y-(-1)=\dfrac{3-(-1)}{\dfrac{1}{2}-(-4)}\times (x-(-4))\\\\y+1=\dfrac{3+1}{\dfrac{1}{2}+4}\times (x+4)\\\\y+1=\dfrac{4}{\dfrac{9}{2}}\times (x+4)\\\\y+1=\dfrac{4\times 2}{9}\times (x+4)\\\\y+1=\dfrac{8}{9}\times (x+4)\\\\9\times (y+1)=8\times (x+4)\\\\9y+9=8x+8\times 4\\\\9y+9=8x+32\\\\8x-9y=9-32\\\\8x-9y=-23$

Hence the equation of line is:

$8x-9y=-23$

5 0

2 years ago

Take 2y 2 - 3y - 5 from y 3 - 6y 2 + 5y. Select the correct answer.

NNADVOKAT [17]

Answer:

$y^3-8y^2+8y+5$

Step-by-step explanation:

Take one polynomial from the other means to perform the sub.traction of them. Recall that it is better to use grouping symbols when subtracting polynomials, so we get the signs right when combining like terms:

The indicated subtraction is: $y^3-6y^2+5y - (2y^2-3y-5)$

Make sure that before removing the grouping symbol (parenthesis) that is preceded by a negative sign, we change the signs of every term inside it. Then combine like terms to get the final answer:

$y^3-6y^2+5y - (2y^2-3y-5)=\\=y^3-6y^2+5y-2y^2+3y+5=\\=y^3-6y^2-2y^2+5y+3y+5=\\=y^3-8y^2+8y+5$