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3 years ago

15 points and you get brainiest if you tell me what I got wrong

Mathematics

2 answers:

Nookie1986 [14]3 years ago

7 0

You added and divided instead of dividing and using the Theron

Ostrovityanka [42]3 years ago

4 0

Answer:

the number is 7611 not 7.611

Step-by-step explanation:

A comma is placed every third digit to the left of the decimal point and so is used in numbers with four or more digits. Continue to place a comma after every third digit. For example: $1,000,000 (one million dollars)

btw the answer is 3,805.5

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Evaluate e – 2 when e=7.

Readme [11.4K]

Answer:

Step-by-step explanation:

If e = 7, you would replace e in the expression e - 2 with 7 so that the expression becomes 7 - 2 which results in 5.

Does that help?

3 0

4 years ago

Read 2 more answers

Use trigonometric substitution to evaluate the integral 13 + 12x − x2 dx . First, write the expression under the radical in an a

SCORPION-xisa [38]

I don't see a square root sign anywhere, so I'll assume the integral is

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx$

First complete the square:

$13+12x-x^2=49-(6-x)^2=7^2-(6-x)^2$

Now in the integral, substitute

$6-x=7\sin t\implies\mathrm dx=-7\cos t\,\mathrm dt$

so that

$t=\sin^{-1}\left(\dfrac{6-x}7\right)$

Under this change of variables, we have

$7^2-(6-x)^2=7^2-7^2\sin^2t=7^2(1-\sin^2t)=7^2\cos^2t$

so that

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx=-7\int\sqrt{7^2\cos^2t}\,\cos t\,\mathrm dt=-49\int|\cos t|\cos t\,\mathrm dt$

Under the right conditions, namely that cos(t) > 0, we can further reduce the integrand to

$|\cos t|\cos t=\cos^2t=\dfrac{1+\cos(2t)}2$

$\displaystyle-49\int|\cos t|\cos t\,\mathrm dt=-\frac{49}2\int(1+\cos(2t))\,\mathrm dt=-\frac{49}2\left(t+\frac12\sin(2t)\right)+C$

Expand the sine term as

$\dfrac12\sin(2t)}=\sin t\cos t$

Then

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \sin t=\dfrac{6-x}7$

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \cos t=\sqrt{7^2-(6-x)^2}=\sqrt{13+12x-x^2}$

So the integral is

$\displaystyle-\frac{49}2\left(\sin^{-1}\left(\dfrac{6-x}7\right)+\dfrac{6-x}7\sqrt{13+12x-x^2}\right)+C$

3 0

3 years ago

The morning announcements said that two out of every seven sixth-grade students in the school have an overdue library book. Jasm

gregori [183]

Answer:

We need to know how many students are in sixth grade and compare the real number with the 84 sixth graders that Jasmine claims to be.

Step-by-step explanation:

We would need to know how many students are in sixth grade to determine who is right. If two students out of seven have an overdue library book and grace claims that 24 of them are overdue by that means, what we would need to do is divide the allegedly 24 students between 2. Now we have 12 pairs of students that have overdue books. For every pair of students in sixth grade that have overdue books, seven students don’t have overdue books, so now we multiply 12 pairs of students with overdue books times 7 students who don’t have overdue books. By Jasmine calculation then, sixth grade have 84 students.

If sixth grade have indeed 84 students, Jasmine is right. If there are not 84 students in sixth grade, she is wrong. Grace is right if there are fewer students than 84 in sixth grade.

Have a nice day! :D

6 0

3 years ago

Points gyfridjwnxsbhjkjh

Art [367]

Answer:hey

Step-by-step explanation:ur cool

7 0

2 years ago

Read 2 more answers

What are the solutions to x2 + 8x + 7 =0?

Nata [24]

The chosen topic is not meant for use with this type of problem. Try the examples below.

y = x+4

y = 2x-5

y = x-1

7 0

3 years ago