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PSYCHO15rus [73]
3 years ago
5

If the perimeter of a rectangular picture frame must be less than 240 in., and the width is 30 in., what must the height h of th

e frame be?
Mathematics
1 answer:
valina [46]3 years ago
3 0

Answer:

64

Step-by-step explanation:

w = width

h = height

2(w+h) < 200

w + h < 100

since w = 36, then

36 + h < 100

h = 100 - 36

h = 64

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Gina shows the steps she took to find the solution of the inequality below.
Leviafan [203]

Answer:

hello,2 th made from the wrong place.

because She should have distributed the -2 inside the parentheses.

the process should be like this;

19-2(1-x)<13

17(1-x)<13

17-17x<13

-17x<13-17 (17 goes to the opposite side as -17)

-17x<-4 (we divide each side by 17)

x= -4/-17

I hope you understand. There are errors in the first 2 parts of the question.

6 0
3 years ago
12r2s + 21rs2 – 3rs=
Nitella [24]
Answer:
63rs

explanation:
collect like terms
12*2=24rs
21*2=42rs
then add 24+42=66rs
then subtract 3rs
then just add rs
6 0
3 years ago
On a​ map, 1 inch equals 9.4 miles. Two houses are 1.5 inches apart on the map. What is the actual distance between the​ houses?
Mumz [18]

Answer:

14.1 I think

Step-by-step explanation:

4 0
3 years ago
In a class of 19 students, 3 are math majors. A group of four students is chosen at random. (Round your answers to four decimal
KatRina [158]

Answer:

(a) The probability is 0.4696

(b) The probability is 0.5304

(c) The probability is 0.0929

Step-by-step explanation:

The total number of ways in which we can select k elements from a group n elements is calculate as:

nCx=\frac{n!}{x!(n-x)!}

So, the number of ways in which we can select four students from a group of 19 students is:

19C4=\frac{19!}{4!(19-4)!}=3,876

On the other hand, the number of ways in which we can select four students with no math majors is:

(16C4)*(3C0)=(\frac{16!}{4!(16-4)!})*(\frac{3!}{0!(3-0)!})=1820

Because, we are going to select 4 students form the 16 students that aren't math majors and select 0 students from the 3 students that are majors.

At the same way, the number of ways in which we can select four students with one, two and three math majors are 1680, 360 and 16 respectively, and they are calculated as:

(16C3)*(3C1)=(\frac{16!}{3!(16-3)!})*(\frac{3!}{1!(3-1)!})=1680

(16C2)*(3C2)=(\frac{16!}{2!(16-2)!})*(\frac{3!}{2!(3-1)!})=360

(16C1)*(3C3)=(\frac{16!}{1!(16-1)!})*(\frac{3!}{3!(3-3)!})=16

Then, the probability that the group has no math majors is:

P=\frac{1820}{3876} =0.4696

The probability that the group has at least one math major is:

P=\frac{1680+360+16}{3876} =0.5304

The probability that the group has exactly two math majors is:

P=\frac{360}{3876} =0.0929

6 0
3 years ago
Terry flips a coin 150 times.Make a prediction that the coin will come up tales
Vinvika [58]

Answer:

its either C or D

Step-by-step explanation:

there are 2 possible outcomes for getting either heads or tails so if we divided 150 by 2 we get 75, so about 75 times you could get tails.

so maybe it is D, but im not sure

5 0
3 years ago
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