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aliya0001 [1]
3 years ago
10

What is 33 over 55 and how do you simplify it.

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
\frac{33}{55}= \frac{33\div11}{55\div11}=\boxed {\frac{3}{5}   }
Ilia_Sergeevich [38]3 years ago
4 0
33/55 = 0.6 
you can simplify this question by dividing both the numerator and denominator by 11 which results in the fraction 3/5
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Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides.
Feliz [49]

Answer:

- 34 < x < 10

Step-by-step explanation:

Inequalities of the type | x | < a, always have a solution of the form

- a < x < a

given | x + 12 | + 5 < 27 ( subtract  5 from both sides )

| x + 12 | < 22, then

- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )

- 34 < x < 10


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3 years ago
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Answer:

D

Step-by-step explanation:

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F(x+h) = (x+h)² + 3(x+h)^3<br><br> How would I distribute this?
Leno4ka [110]

Answer:

f(x + h) = 3x³ + x² + 9h²x + 3h³ + h² + 9hx² + 2hx

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distributive Property
  • Expand by FOIL (First Outside Inside Last)
  • Combining like terms

Step-by-step explanation:

<u>Step 1: Define function</u>

f(x) = x² + 3x³

f(x + h) is x = x + h

<u>Step 2: Simplify</u>

  1. Substitute:                              f(x + h) = (x + h)² + 3(x + h)³
  2. Expand by FOILing:               f(x + h) = (x² + 2hx + h²) + 3(x + h)³
  3. Rewrite:                                  f(x + h) = (x² + 2hx + h²) + 3(x + h)²(x + h)
  4. Expand by FOILing:               f(x + h) = (x²+2hx+h²) + 3(x² + 2hx + h²)(x+h)
  5. Distribute/Expand:                 f(x + h) = (x²+2hx+h²) + 3(x³+3hx²+3h²x+h³)
  6. Distribute 3:                            f(x + h) = (x²+2hx+h²)+(3x³+9hx²+9h²x+3h³)
  7. Combine like terms:               f(x + h) = 3x³+x²+9h²x+3h³+h²+9hx²+2hx
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3 years ago
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PIT_PIT [208]

They would make $11.77 :)

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What is 2p + 5r = q for p
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Subtract 5r from both sides
2p= q-5r
Divide both sides by 2
p= (q-5r)/2
4 0
3 years ago
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