Question

Simplify surds √50+√√72-√√128​

Answer 1

Answer:

3$\sqrt{2}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the given radicals

$\sqrt{50}$

= $\sqrt{25(2)}$

= $\sqrt{25}$ × $\sqrt{2}$

= 5$\sqrt{2}$

------------------------

$\sqrt{72}$

= $\sqrt{36(2)}$

= $\sqrt{36}$ × $\sqrt{2}$

= 6$\sqrt{2}$

-----------------------

$\sqrt{128}$

= $\sqrt{64(2)}$

= $\sqrt{64}$ × $\sqrt{2}$

= 8$\sqrt{2}$

Then

$\sqrt{50}$ + $\sqrt{72}$ - $\sqrt{128}$

= 5$\sqrt{2}$ + 6$\sqrt{2}$ - 8$\sqrt{2}$

= 11$\sqrt{2}$ - 8$\sqrt{2}$

= 3$\sqrt{2}$