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2 years ago

Simplify surds √50+√√72-√√128

Mathematics

1 answer:

34kurt2 years ago

3 0

Answer:

3 $\sqrt{2}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the given radicals

$\sqrt{50}$

= $\sqrt{25(2)}$

= $\sqrt{25}$ × $\sqrt{2}$

= 5 $\sqrt{2}$

------------------------

$\sqrt{72}$

= $\sqrt{36(2)}$

= $\sqrt{36}$ × $\sqrt{2}$

= 6 $\sqrt{2}$

-----------------------

$\sqrt{128}$

= $\sqrt{64(2)}$

= $\sqrt{64}$ × $\sqrt{2}$

= 8 $\sqrt{2}$

Then

$\sqrt{50}$ + $\sqrt{72}$ - $\sqrt{128}$

= 5 $\sqrt{2}$ + 6 $\sqrt{2}$ - 8 $\sqrt{2}$

= 11 $\sqrt{2}$ - 8 $\sqrt{2}$

= 3 $\sqrt{2}$

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2 years ago

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Answered by Guathmath

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3 years ago

calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-

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Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

1. A (1,5), B (4,5) (red)

$d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}$

2. A (2,-5), B (2,7) (blue)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}$

3. A (3,1), B (-1,4 ) (green)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}$

4. A (-2,-5), B (3,7) (orange)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}$

5. A (5,4), B (-3,-2) (purple)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}$

6. A (1,-8), B (-5,0) (black)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}$

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3 years ago

4x^2-400=0<br><br> square roots and solving quadratics

posledela

Answer:

x = ±10

Step-by-step explanation:

4x² - 400 = 0

Add 400 to both sides

4x² = 400

Divide both sides by 4

x² = 100

Take the square root of both sides

x = ±10

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3 years ago

Shapes that always have perpendicular lines

amm1812

A couple of shapes that have perpendicular lines are right triangles, and rectangles.

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3 years ago

Simplify surds √50+√√72-√√128​

Simplify surds √50+√√72-√√128