The app uses 2^28 bytes.
Step-by-step explanation:
- Step 1: Given total storage used by the app = 4^4 Megabytes. Also, 1 MB = 2^20 bytes. Find total storage used by app in bytes.
⇒ 4^4 × 2^20 = (2²)^4 × 2^20 = 2^8 × 2^20
= 2^8+20
= 2^28 bytes (using the law of exponents a^m × a^n = a^m+n)
Answer:
frfrfr
Step-by-step explanation:
Step-by-step explanation:
(x²-1)(x+1)≥0
As it has two multiples,
Therefore,
Either,
x²-1≥0
x²≥0+1
x²≥1
x≤√1
x≤1
Or,
x+1≥0
x≥-1
The answer will be p+q+r, or p+r+q, or q+p+r. Hope it help!
Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
