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RideAnS [48]
3 years ago
7

Is -16/-2 rational or irrational?

Mathematics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

Totally Rational

Step-by-step explanation:

-16/-2 would give you 8 which is a rational number

<em><u>I hope this helps, dont hesitate to ask for any question.Mark me as brainliest is appreciated.Tq!!</u></em>

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Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...
svlad2 [7]

Answer:

The required recursive formula is:

a_n=(-3)\times a_{n-1}

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let a_n represents the nth term of the sequence.

This means that:

a_1=6, a_2=-18, a_3=54, a_4=-162,......

As the common ratio is -3.

so,

a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}

Hence, the required recursive formula for the geometric sequence is:

a_n=(-3)\times a_{n-1}

5 0
3 years ago
What is 41.073 rounded to 0
lora16 [44]
41.1 is the answer to this question.
4 0
3 years ago
bill bought a new cellular phone. his monthly bill will be $34.99 each month which includes 100 minutes of use. additional minut
Alenkinab [10]
$34.99 + $0.23m = c
or
c = $0.23m + $34.99
3 0
3 years ago
Read 2 more answers
PLEASE HELP! I'm on a timer!
arlik [135]
The equation of a circle uses the following formula:

(x - h)^{2} + (y - k)^{2} = r^{2}

The center of the circle is given by (h,k). Therefore, h = -2, and k = -5. r = 1, so we can find the equation from the information given to us.

Plug in your values.

(x + 2)^{2} + (y + 5)^{2} = 1^{2}

1^{2} = 1

The equation of this circle is as follows:

(x + 2)^{2} + (y + 5)^{2} = 1
8 0
3 years ago
24 is what percent of 96?​
Andrei [34K]

Answer: 25%

Step-by-step explanation:

make it into a fraction

24/96 then simplify

decimal answer is .25

move the decimal to the right 2 times

7 0
2 years ago
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