Answer:
You can look at the screenshot
Step-by-step explanation:
So one point of the line is (0, -4) and another point is (4/3, 0). Plot these points on a graph and draw a line.
0, -4 is from making x = 0, and then 4/3, 0 is from making y = 0.
well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Answer:

Step-by-step explanation:

Given integral:



Using <u>integration by parts</u>:


Therefore:





Therefore:



Divide both sides by 2:

Rewrite in the same format as the given integral:

The answer is <span>-(3/4) and 3/4</span>