Answer:

Step-by-step explanation:
Solve by substitution. Solve the second equation for x:

Insert the value of x into the first equation:

Solve for y. Simplify multiplication using the distributive property:

Subtract 190 from both sides:

Isolate the variable to find its value. Divide both sides by -29:

Now take the value of y and insert back into either equation to solve for x:

Subtract 6 from both sides:

Divide both sides by 5:

Therefore, the solution to the system is
.
:Done
I think the answer to y when x=4 and z=15; if y varies jointly as x and z y=5 when z=8 and x=10 is B. Y=1/2. Y•15; 12/4.
The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
<h3>How to type the ordered pairs?</h3>
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
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