No x = -10 cannot be an input value because the x is the number of students , which can only be from 0 and above. You cannot have negative students.
BY USING MIDDLE TERM SPLITTING,
3y^2-(3y-2y)-2
(3y^2-3y)+(2y-2)
3y(y-1)+2(y-1)
(3y+2)(y-1)
HOPE THIS WILL HELP U
The answer to the first question is b
I don’t know the answer to the second one sorry
Multiply the area of the circle by the percentage:
60 square units x 50% = 60 x 0.50 = 30
50% 0f the circle id 30 square units.
