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Degger [83]
3 years ago
9

A shaky story.Taylor and Jordan were known for throwing a heck of a good party. At one of their wild gatherings, five couples we

re present including Taylor and Jordan. The attendees were cordial, and some even shook hands with other guests. Although we have no idea who shook hands with whom, we do know that no one shook hands with themselves and no one shook hands with his or her own partner. Given these facts, a guest might not shake anyone's hand or might shake as many as eight other people's hands. At midnight, Jordan gathered the crowd and asked the nine other people how many hands each of them had shaken.
Much to Jordan's amazement, each person gave a different answer. That is, someone didn't shake any hands, someone else shook one hands, someone else shook two hands, someone else shook three hands, and so forth, down to the last person, who shook eight hands. Given this outcome, determine the exact number of hands that Taylor shook.
Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

i dont know but that must've been a good party

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1
kherson [118]

Answer:

6000cm

Step-by-step explanation:

multiply all figures given

7 0
3 years ago
What are the quotient and remainder of (x^5-x^3+-5) divided by (x-2)
pishuonlain [190]

Answer:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

Step-by-step explanation:

You can do this through synthetic division. It is a shorthand way of dividing polynomials.

First you need to make your divisor equal to zero so you can solve for what goes into the division box:

x - 2 = 0 →     x = 2

The next step is to arrange your polynomials in descending powers. All missing terms, you will put in a zero.

x⁵ - x³ + (-5)   →  x⁵ + 0x⁴- x³ + 0x² + 0x + (-5)

Now you can proceed to synthetic division. Make an upside down division box with the divisor outside and the coefficients of the dividend listed, along with their sign. Leave a space below the divident

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

Next you bring down the first coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

        +1    

Then you multiply it by the divisor and write the product under the next coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>           +2                                   </u>

        +1    

Next add the column and put the sum below it:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2                                   </u>

        +1    +2

Then multiply again and repeat until you reach the last coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2    +4   +6   +12   +24 </u>

        +1    +2    +3   +6   +12    +19

Now that you have your results, add  in the x and their powers. The powers will start with the highest power but 1 less than the dividend. Since the dividend's highest power is 5, then the quotient's highest power will be 4. Then write it in descending order :

+1x⁴    +2x³    +3x²   +6x   +12   +19

Now the last coefficient is your remainder. So your results will be:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

7 0
4 years ago
Read 2 more answers
Geometry unit 2 help please?
Alja [10]

Answer: Segemnt BD is congurent to segment BD. This is true based off of the reflexive property, something is equal to itself. Also i think i go to the same school as you lol

4 0
3 years ago
Help! Quick please!
Vesnalui [34]
B..............
c>=3 and n<0 and p<=(9-3 c)/n
8 0
3 years ago
Read 2 more answers
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
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