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vitfil [10]
3 years ago
14

Help with finding the volume of the cone pictured

Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Volume of the cone = 56.52 in³

Solution:

Diameter of the cone = 6 in

Radius of the cone = 6 ÷ 2 = 3 in

Height of the cone = 6 in

The value of π = 3.14

<u>To find the volume of the cone:</u>

Volume of the cone = \frac{1}{3} \pi r^{2} h

                                 $=\frac{1}{3} \times 3.14 \times 3^{2} \times 6

                                 $=3.14 \times 18

                                 = 56.52

Volume of the cone = 56.52 in³

Hence the volume of the given cone is 56.52 \text{in}^3.

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<h3>What is an equation?</h3>

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a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\

When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\

The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

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