Answer:
70
Step-by-step explanation:
RU=20 (45-45-90 triangle)
use pythagorean theorum
20^2+b^2=73^2
evaluate
b^2=4929
sq root both side
rounded to nearest integer, side SU is 70
Given that 
and 
, we can say the following:
Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).
Thus, let's set what is under both square roots to be greater than 0:
Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.
Now, let's look back at the function entirely, which is:
Since 
is on the bottom of the fraction, we must say that 
, since the denominator can't equal 0. Thus, we must exclude 
from the domain.
Thus, our answer is Choice C, or 
.
<em>If you are wondering why the choices begin with the 
symbol, it is because this is a way of representing that 
lies within a particular set.</em>
Answer:
d. fourteen fortieths
Step-by-step explanation:
i believe this is correct.
So let's start by guesstimating the slopes:
the green line has a slope close to -x, but more negative than that, possibly -2; the pink line has a slope close to +x, but higher towards +2.
Next let's look at the solution: the two lines intersect at the point (1, -1).
**you could just simple plug that x (1) into all the equations, but let's rule out answers anyway. ;)
A) is incorrect because the slopes of -1 and +1 are off from out predicted -2 and +2
B) is incorrect because of a similar reason, the slopes of +3 and +1 don't make any sense
C) Ooh, we do have a +2 and -2 for the slopes, and... violà! plug in 1 for the x's and we get -1 for the y in both equations
D) slopes are closer than in A and B, but plugging in 1 doesn't get us -1
So the correct answer is:
C) y = 2x - 3 and y = −2x + 1
Answer:
36
Step-by-step explanation:
Area of total region = 12 ×5
=60
Area of the small region = 8×3
=24
Area of shaded region = Area of Total region - area of small region
= 60 - 24
= 36
