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algol [13]
3 years ago
14

**Answers needed fast** Jason says his measurement is larger than Marco’s measurement because

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

Jason is not correct because 0.819 is not larger than 0.85. Marco's number is larger.

You might be interested in
(with steps please)
Yuki888 [10]

Answer:

  • 21 of multiple choice and 17 of short answer questions

Step-by-step explanation:

  • Multiple choice = m
  • Short answer = s

<u>Equations:</u>

  • m + s = 38
  • 2m + 3s = 93

<u>Solve for s by eliminating m. Subtract the double of the first equation from the second one:</u>

  • 2m + 3s - 2(m + s) = 93 - 2(38)
  • 3s - 2s = 93 - 76
  • s = 17

<u>Find the value of m:</u>

  • m = 38 - 17 = 21
3 0
3 years ago
At the movie theatre, child admission is $5.90 and adult admission is $9.70 . On Tuesday, 168 tickets were sold for a total sale
Sergeu [11.5K]
X= child ticket
y= adult ticket

COST EQUATION:
$5.90x + $9.70y=$1352.20
QUANTITY EQUATION:
x+y=168

Step 1:
Solve for one variable in either equation and substitute it in the other equation

x+y=168

subtract y from both sided
x=168-y

Step 2:
substitute x=168-y in other equation

5.90x + 9.70y=1352.20
5.90(168-y) +9.70y=1352.20

multiply 5.90 by everything in parentheses
(5.90*168)+(5.90*-y) +9.70y=1352.20
991.20-5.90y+9.70y=1352.20

combine like terms
991.20+3.80y=1352.20

subtract 991.20 from both sides
3.80y=361

divide both sides by 3.80
y=95 adult tickets

There were 95 adult tickets sold.

Hope this helps! :)



3 0
4 years ago
The sum of two numbers is 12 and their difference is 20. What is the smaller number?
zhannawk [14.2K]

Answer:

16 and -4

Step-by-step explanation:

Let the 2 numbers be x and y with x > y

x+y=12

x-y=20

Adding the 2 equations, term by term on both sides, will eliminate y leaving an equation in x that we can solve

(x+x)+(-y+y)=(12+20)

2x=32

x=16

16+y=12

y=-4

16+-4=12

12=12

16--4=20

20=20

3 0
3 years ago
A random sample of 150 recent donations at a certain blood bank reveals that 82 were type A blood. Does this suggest that the ac
kati45 [8]

Answer:

We  reject H₀   Porcentage of type A blood  donations differs from 40% (porcentage of population having type A blood)

Step-by-step explanation:

We are going to develop a proportion test.

Information we have:

Proportion   P₀   =  40 %      P₀   =  0,4  (porcentage of population having type A blood)

Sample size    n   =   150

Sample  mean   P  =  82/ 150      P  = 0,5466

As  P₀  =   0,4      Q₀  =  0,6     P₀*Q₀   =  0,24

1.-Test Hypothesis:

H₀    null hypothesis                            P₀   =   0.4

Hₐ   alternative hypothesis                 P₀   ≠   0.4

2.- signficance level

     a  )   α  =  0.01    we have a two tail-test      α/2    =   0.005  

     b  )   α  =  0.05                                               α/2    =   0.025

Then  from t-student table we get t(c)   n  = 150    df =  149

     a  )   α/2    =   0.005             t(c)    =  2.581

     b  )   α/2    =   0.025             t(c)    =  1.962

3.-Compute t(s)

t(s)   =   (  P  -  P₀ )  / √P₀Q₀/n  

Plugging  in known values  

t(s)   =[ ( 0.5466 -  0,4  )*√150 ] / √0.24

t(s)   = 0,1466 * 12.25 / 0.4899

t(s)   =  3.6657

Compare t(s)  and  t(c)

t(s)  >  t(c)       3.6657  >  2.581      

Then  t(s) is out of the acceptance region  we reject  H₀.

Simple inspection led us see that for

α/2    =   0.025             t(c)    =  1.962

The situation is the same

6 0
3 years ago
Answer these questions please I'm really desperate. please im going to fail if I dont get this right
Drupady [299]

<u>Answer-</u>

g(x)=-3x

<u>Solution</u>-

First of all we have to get the value of f, as two point (0, -1) and (1, 2), we can get the equation by applying two point formula of straight line.

\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}

\Rightarrow \dfrac{y+1}{2+1}=\dfrac{x-0}{1-0}

\Rightarrow \dfrac{y+1}{3}=\dfrac{x}{1}

\Rightarrow \dfrac{y+1}{3}=x

\Rightarrow {y+1}=3x

\Rightarrow y=3x-1

\Rightarrow f(x)=3x-1

Translating any point with coordinate as (x,y) 1 unit down, becomes (x, y-1)

So the new function will be,

\Rightarrow (y-1)=3x-1

\Rightarrow y=3x

Reflecting any point with coordinate as (x,y) over x axis, becomes (x, -y)

So the new function will be,

\Rightarrow -y=3x

\Rightarrow y=-3x

\Rightarrow g(x)=-3x

3 0
3 years ago
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