Answer:
Step-by-step explanation:
Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.
G = card drawn is green
Y = card drawn is yellow
E = card drawn is even-numbered
List:
Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}
2) P(G) = 5/8
3) P(G/E) = P(GE)/P(E)
GE = {G2, G4}
Hence P(G/E) = 2/5
4) GE = {G2, G4}
P(GE) = 2/8 = 1/4
5) P(G or E) = P(G)+P(E)-P(GE)
= 5/8 + 3/8-2/8 = 3/5
6) No there is common element as G2 and G4
Cannot be mutually exclusive
Answer:
Step-by-step explanation:
part a: time, student surf the internet
part b
Every number will have only 3 digits. In the ones place, there are 5 choices. For every choice of digit made in the ones place, there are 8 possible choices for the hundreds place (you can choose from 1-9, omitting whatever is used in the ones place), and there are 8 possible choices for the tens place (you can choose from 0-9, omitting whatever has already been used elsewhere).
So there are
such numbers.
The lcd would be 10x^3y^3
Answer:
x² - 100
Step-by-step explanation:
Use the FOIL method. The FOIL method is the way in which you multiply the terms:
FOIL stands for First, Outside, Inside, Last. Multiply:
First:
x * x = x²
Outside:
x * 10 = 10x
Inside:
-10 * x = -10x
Last:
-10 * 10 = -100
Combine like terms:
x² + 10x - 10x - 100
x² + (10x - 10x) - 100
x² - 100
x² - 100 is your answer.
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