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skad [1K]
3 years ago
13

Last spring, the drama department at Manchester High School had 12 students audition for the musical. This spring, there were 15

students trying out. What is the percent of increase in the number of students auditioning?
I'm reposting this because no one has answered it yet
Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

25%

Step-by-step explanation:

The percent of increase can be calculated using following formula:

\text{Percent Increase}=\dfrac{\text{Final Amount-Initial Amount}}{\text{Initial Amount}}\cdot 100\%.

In your case,

  • Initial amount = 12 students;
  • Final amount = 15 students,

then

\text{Percent Increase}=\dfrac{15-12}{12}\cdot 100\%=\dfrac{3}{12}\cdot 100\%=\dfrac{1}{4}\cdot 100\%=25\%.

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☆+☆+☆=18<br>♡+♡+☆=14<br>♤+♤+♡=2<br>♡+♤+☆☆=<br><br>Genius only look closely at the details ​
Dmitriy789 [7]

Answer:

15

Step-by-step explanation:

3 stars = 18

1 star = 6

14-6=8/2 = 4

1 heart = 4

1 spade = -1

4 + -1=  3

3 + (2 stars)

3 + 12 = 15

5 0
3 years ago
The equation of line a is y=3/4x-3 If line b runs parallel to line a and passes
katen-ka-za [31]

Answer:

y = -4/3 x - 1/3

Step-by-step explanation:

y = -4/3 x + b

5 = -4/3 (-4) + b

15 = 16 + 3b

b = -1/3

y = -4/3 x - 1/3

5 0
2 years ago
Line segment CD is shown on a coordinate grid:
Lady_Fox [76]

Answer:

im pretty sure the answer would be C'D' and CD would be equal in length!

Step-by-step explanation:

because you are only reflecting it across the y-axis, no changes will be made to the line itself, only the location of the line :)

7 0
3 years ago
Read 2 more answers
Please help me solve. <br> Thanks.
Slav-nsk [51]

Answer:

The last one is correct

4 0
3 years ago
Read 2 more answers
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
2 years ago
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