The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer: b
Step-by-step explanation:
best sample
We start at 62 Fahrenheit. And every hour we drop two degrees. We want to know how long it took for the temperature to drop to 40 Fahrenheit.
If one hour passed, then the temperature dropped two degrees.
If two hours passed, then the temperature dropped 4 degrees.
See the pattern? We can define this as 2h. Where h represents time in hours.
We subtract 2h from 62.
We can write this as a function. F(h) = 62 - 2h.
Where F is the temperature in Fahrenheit. And h is the hour(s).
Now that we have the formula, let's plug in the value 40 Fahrenheit to see how long it took for the temperature to drop to 40 degrees.
40 = 62 - 2h
Subtract 62 from each side
-22 = -2h
Divide both sides by 2
h = 11
So, it took 11 hours for the temperature to drop to 40 Fahrenheit.
B is your awnser! sorry if im wrong my calc shows its without a - symbol
Equation is 4b + 5m = €10.90, and values of b and m are €1.35 and €1.1 respectively.
Step-by-step explanation:
- Step 1: Find equation for Thursday's sales.
Given b = price of a loaf of bread and m = price of one liter of milk
Total sales = €10.90
Equation ⇒ 4b + 5m = €10.90
- Step 2: Find the values of b and m.
3b + 2m = 6.25 ----- (1)
4b + 5m = 10.90 ---- (2)
Multiply eq(1) by 5 and eq(2) by 2 to make coefficients of m equal.
15b + 10m = 31.25
8b + 10m = 21.8
Subtract eq(2) from eq(1)
⇒ 7b = 9.45
⇒ b = 9.45/7 = €1.35
Substitute for b and find m using eq(1).
⇒ 3 × 1.35 + 2m = 6.25
⇒ 4.05 + 2m = 6.25
⇒ 2m = 2.2
∴∴ m = 2.2/2 = €1.1