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3 years ago

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Last spring, the drama department at Manchester High School had 12 students audition for the musical. This spring, there were 15

students trying out. What is the percent of increase in the number of students auditioning?
I'm reposting this because no one has answered it yet

1 answer:

tamaranim1 [39]3 years ago

3 0

Answer:

25%

Step-by-step explanation:

The percent of increase can be calculated using following formula:

$\text{Percent Increase}=\dfrac{\text{Final Amount-Initial Amount}}{\text{Initial Amount}}\cdot 100\%.$

In your case,

Initial amount = 12 students;
Final amount = 15 students,

then

$\text{Percent Increase}=\dfrac{15-12}{12}\cdot 100\%=\dfrac{3}{12}\cdot 100\%=\dfrac{1}{4}\cdot 100\%=25\%.$

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I need help I don’t understand and I need to show my work who would help me??

stich3 [128]

Answer: b

Step-by-step explanation:

In the last question, you wrote on a second equation "13x ...." kkk

Let's go:

We have to check each one answer in the following system:

x - 2y = 7

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I can use the substituition method to solve this system...

x = 7 + 2y

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Finally, the correct answer is the second one (letter b).

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3 years ago

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4% of what number is 40?

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Step-by-step explanation: you do 4% multiplied by x = 40

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Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}

Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3> </h3>

To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by $\large \sf a^{n}.$ The terms of a power are:

<h3> </h3>

Base
Exponent
equal factors
power

<h3> </h3>

✏️ <u>Resolution/Answer</u>:

$\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\$

Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

$\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\$

<em>Multiply </em>the power at denominator of the fraction:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\$

<em>Multiply </em>the numerator numbers together:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=$

$\large \sf \dfrac{-16\cdot16\cdot 256 }{16}=$

$\large \sf \dfrac{-256\cdot 256 }{16}=$

$\large \sf \dfrac{- 65536 }{16}=\\\\$

Simplify the fraction by number 16:

$\\\large \sf \dfrac{- 65536 }{16}=$

$\large \sf \dfrac{- 65536 \div16}{16\div16}=$

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}} \\\\\\$

So this expression in its simplified form = -4096/1 or -4096.

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}}\\\\$

★ Hope this helps! ❤️

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Firdavs [7]

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zysi [14]

Answer:

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Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

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$y =A \sin(Bx + C) + D$

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So:

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So, we have:

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$Period = \frac{2\pi}{1}$

$Period = 2\pi$

Hence, the period of the function is $2\pi$

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3 years ago