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skad [1K]
3 years ago
13

Last spring, the drama department at Manchester High School had 12 students audition for the musical. This spring, there were 15

students trying out. What is the percent of increase in the number of students auditioning?
I'm reposting this because no one has answered it yet
Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

25%

Step-by-step explanation:

The percent of increase can be calculated using following formula:

\text{Percent Increase}=\dfrac{\text{Final Amount-Initial Amount}}{\text{Initial Amount}}\cdot 100\%.

In your case,

  • Initial amount = 12 students;
  • Final amount = 15 students,

then

\text{Percent Increase}=\dfrac{15-12}{12}\cdot 100\%=\dfrac{3}{12}\cdot 100\%=\dfrac{1}{4}\cdot 100\%=25\%.

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I need help I don’t understand and I need to show my work who would help me??
stich3 [128]

Answer: b

Step-by-step explanation:

In the last question, you wrote on a second equation "13x ...." kkk

Let's go:

We have to check each one answer in the following system:

x - 2y = 7

3x + 7y = 8

I can use the substituition method to solve this system...

x = 7 + 2y

3x + 7y = 8

3(7 + 2y) + 7y = 8

21 + 6y + 7y = 8

13y = 8 - 21

13y = -13

y = -1

x = 7 + 2.(-1)

x = 5

Finally, the correct answer is the second one (letter b).

5 0
3 years ago
Read 2 more answers
4% of what number is 40?
ladessa [460]

Answer: 1000

Step-by-step explanation: you do 4% multiplied by x = 40

Multiplying both sides by 100 and dividing both sides by 4,

we have x = 40 × 100/4

40×100÷4

And you get 1000

4 0
3 years ago
Read 2 more answers
Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}
Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3>   </h3>
  • To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by \large \sf a^{n}. The terms of a power are:

<h3>     </h3>
  • Base
  • Exponent
  • equal factors
  • power
<h3>         </h3>

✏️ <u>Resolution/Answer</u>:

\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\

  • Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\

  • <em>Multiply </em>the power at denominator of the fraction:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\

  • <em>Multiply </em>the numerator numbers together:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=

\large \sf \dfrac{-16\cdot16\cdot 256     }{16}=

\large \sf \dfrac{-256\cdot 256     }{16}=

\large \sf \dfrac{- 65536  }{16}=\\\\

  • Simplify the fraction by number 16:

\\\large \sf \dfrac{- 65536  }{16}=

\large \sf \dfrac{- 65536  \div16}{16\div16}=

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}} \\\\\\

  • So this expression in its simplified form = -4096/1 or -4096.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}}\\\\

                                 ★ Hope this helps! ❤️

6 0
3 years ago
We bought five 3 3/4 pound bags of bird seed. What is the total weight of the birdseed they bought
Firdavs [7]
It would be 18.75 because if you put it into a mixed number then multiply by 5 you get 18.75
3 0
3 years ago
Determine the amplitude or period as requested. Period of a y = - 1/3 * sin x - 1/3 pi/3 1/3 d 2pi
zysi [14]

Answer:

Period = 2\pi

Step-by-step explanation:

Given

y = -\frac{1}{3} * \sin(x - \frac{1}{3})

Required

Determine the period

A sine function is represented as:

y =A \sin(Bx + C) + D

Where

Period = \frac{2\pi}{B}

By comparing:

y =A \sin(Bx + C) + D and y = -\frac{1}{3} * \sin(x - \frac{1}{3})

Bx = x

So:

B = 1

So, we have:

Period = \frac{2\pi}{B}

Period = \frac{2\pi}{1}

Period = 2\pi

Hence, the period of the function is 2\pi

6 0
3 years ago
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