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mr_godi [17]
3 years ago
13

What type of reaction is the decay of carbon-14

Chemistry
1 answer:
wel3 years ago
5 0
First Order Reaction 
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1) Calculate the molar mass of Tryptophan.
mestny [16]

Answer:

204.23 g/mol

Explanation:

6 0
3 years ago
Which statement is a valid conclusion about the activation energy of the reverse reaction if the forward reaction is exothermic?
babunello [35]

Answer:

e) The activation energy of the reverse reaction is greater than that of the forward reaction.

Explanation:

  • Activation energy is the minimum amount of energy that is required by the reactants to start a reaction.
  • An exothermic reaction is a reaction that releases heat energy to the surrounding while an endothermic reactions is a reaction that absorbs heat from the surrounding.
  • <em><u>In reversible reactions, when the forward reaction is exothermic it means the reverse reaction will be endothermic, therefore the reverse reaction will have a higher activation energy than the forward reaction.</u></em> The activation energy of the reverse reaction will be the sum of the enthalpy and the activation energy of the forward reaction.
4 0
4 years ago
A. How many protons, electrons, and neutrons make up an atom
mestny [16]

Answer:

45 neutrons

Explanation:

Bromine has 35 protons and a mass number of 80. a) How many neutrons does the atom of bromine have? The mass number = protons + neutrons. Bromine has a mass number of 80 and 35 protons so 80-35 = 45 neutrons.

5 0
2 years ago
A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?
uranmaximum [27]

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

  • Hafnium = 55.7% = 55.7g
  • Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

  • Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
  • Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

  • Hafnium = 0.312 ÷ 0.312 = 1
  • Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

#SPJ1

7 0
1 year ago
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)<br><br> Which type of reaction is this?
erastova [34]

Answer: Combustion

Explanation:

3 0
1 year ago
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