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kvv77 [185]
3 years ago
8

Khjgjhgfmhgxfhkugfdnhmvngchnvnhvhgh

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
5 0

Answer:

I don’t know

Explanation:

bazaltina [42]3 years ago
4 0

Answer: fish are ghosts

Explanation:

Water, space, oxygen. What do they have in common? What do they have that is unique to themselves? One must ponder life’s hidden truths in order to gain true and pure enlightenment.

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Hiw to separate and measure a mixture of iron fillings, sugar, and salt
Alecsey [184]
Add water to mixture to dissolve sugar then filter. sugared water will be the filtrate while the salt & iron fillings will be the residue. use magnet to attract iron fillings and remaining will be salt.
3 0
3 years ago
Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
Which substances will make a salt when combined?
BartSMP [9]
Vinegar and tea for sure
3 0
2 years ago
Type the correct answer in each box.
Luba_88 [7]

Answer:  The weight of the object on earth =441N

Weight of the object on moon = 72N

6 0
3 years ago
The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1
IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }

Where S_{1} is the initial solubility

P_{1} is the initial pressure

S_{2} is the final solubility

P_{2} is the final pressure

From the given information

S_{1} = 0.890 \ g/L

P_{1} = 120 \ kPa

P_{2} = 100 \ kPa

Putting the parameters into the formula, we get

\frac{0.890}{120}=\frac{S_{2}}{100}

S_{2}= \frac{0.890 \times 100}{120}

S_{2}= 0.742 \ g/L

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

7 0
2 years ago
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