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3 years ago

Can somebody show me step by step how to solve this?

Mathematics

2 answers:

forsale [732]3 years ago

8 0

Step-by-step explanation:

First, apply power rule

$\frac{1}{ - 4 \times - 4 \times - 4} = \frac{1}{ - 64}$

$- \frac{1}{64}$

Volgvan3 years ago

6 0

Answer:

$\frac{1}{-64}$

Step-by-step explanation:

Reduce the expression, if possible, by canceling the common factors.

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Write an equation in intercept form of the parabola that passes through the point (3,40) and has x-intercepts −5 and 4.

Maru [420]

The equation of this parabola will have the form f(x) = a(x+5)(x-4), which works out to f(x) = a(x^2 + x - 20). Since the parabola passes thru (3,40),

40 = a(3^2 + 3 - 20), or 40 = a(-8), so a = -5.

Thus, the equation of this parabola is y = -5(x^2 + x - 20).

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3 years ago

2. Given that a = 3 , b = 2, and c = −1, evaluate each of the following expressionsa) (a+3b)

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Answer:

Step-by-step explanation:

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8 tables will be in each row because 8 times 8 would be 64

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3 years ago

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3 years ago

What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – and x = –2 + x = –2 – and x = –2 + x = 2 – and x = 2

Scorpion4ik [409]

The given quadratic function is:

$f(x)=2 x^{2} +8x-3$

The zeros of the quadratic functions also known as its roots can be found using the quadratic formula.

According to the quadratic formula:

$x= \frac{-b+- \sqrt{ b^{2}-4ac } }{2a}$
here,
b = coefficient of x-term
a = coefficient of x²-term
c = costant term

For given function:
a = 2
b = 8
c = - 3

Using these values in the formula, we get:

$x= \frac{-8+- \sqrt{64-4(2)(-3)} }{2(2)} \\ \\ 
x= \frac{-8+- \sqrt{88} }{4} \\ \\ 
x= \frac{-8+-2 \sqrt{22}}{4} \\ \\ 
x= \frac{-4+- \sqrt{22} }{2} \\ \\ 
x= \frac{-4+ \sqrt{22} }{2}, x= \frac{-4- \sqrt{22} }{2}$

Thus, these values of x are the zeros of the given quadratic function f(x)=2x²+8x-3

4 0

3 years ago

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