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Margaret [11]
4 years ago
9

Drag and drop a statement or reason to each box to complete the proof.

Mathematics
2 answers:
Inga [223]4 years ago
7 0

Answer:

Given : EFGH is a Parallelogram

Prove : EG Bisects HF , HF Bisects EG

Step-by-step explanation:

Proof

Check image below

frozen [14]4 years ago
5 0

Answer:

Given Parallelogram EFGH

EG bisects HF and HF bisects EG, if and only if both the diagnols have same mid point.

Step-by-step explanation:

Step 01:

Let

E be the point (a,b)

F be the point (a',b)

G be the point (a',b')

H be the point (a,b')

Step 02:

Now find mid points of EG and HF

mid point of EG = ( \frac{a+a'}{2}, \frac{b+b'}{2} ) and

mid point of HF = (  \frac{a'+a}{2},\frac{b'+b}{2} )

Since addition is commutative, and they have the same mid-point, so they bisect each other.

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