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Margaret [11]
3 years ago
9

Drag and drop a statement or reason to each box to complete the proof.

Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

Given : EFGH is a Parallelogram

Prove : EG Bisects HF , HF Bisects EG

Step-by-step explanation:

Proof

Check image below

frozen [14]3 years ago
5 0

Answer:

Given Parallelogram EFGH

EG bisects HF and HF bisects EG, if and only if both the diagnols have same mid point.

Step-by-step explanation:

Step 01:

Let

E be the point (a,b)

F be the point (a',b)

G be the point (a',b')

H be the point (a,b')

Step 02:

Now find mid points of EG and HF

mid point of EG = ( \frac{a+a'}{2}, \frac{b+b'}{2} ) and

mid point of HF = (  \frac{a'+a}{2},\frac{b'+b}{2} )

Since addition is commutative, and they have the same mid-point, so they bisect each other.

You might be interested in
JK in the coordinate plane has endpoints with coordinates (-4, 11) and (8,
atroni [7]

Answer:

(0, 7)

Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

JP:JK = 1/3

Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

K(8, -1) = (x_2, y_2)

k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

3 0
3 years ago
PLEASE PLEASE HELP!!!!
Gennadij [26K]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
(6)(−3)(−5) ........................
My name is Ann [436]

Answer:

-2? maybe

Step-by-step explanation:

5 0
3 years ago
-14(3a+6)=12(6-4a)+12 and steps please
Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

a=\frac{168}{6}

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0
3 years ago
Any help with this plzzz?????
Harrizon [31]
1.
a.11/12=less than one

b. 77/72= greater than one

c.23/60= less than one

d. 31/56= less than one

2. <
8 0
3 years ago
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