Drag and drop a statement or reason to each box to complete the proof.
2 answers:
Answer:
Given : EFGH is a Parallelogram
Prove : EG Bisects HF , HF Bisects EG
Step-by-step explanation:
Proof
Check image below
Answer:
Given Parallelogram EFGH
EG bisects HF and HF bisects EG, if and only if both the diagnols have same mid point.
Step-by-step explanation:
Step 01:
Let
E be the point (a,b)
F be the point (a',b)
G be the point (a',b')
H be the point (a,b')
Step 02:
Now find mid points of EG and HF
mid point of EG = ( ,
) and
mid point of HF = ( ,
)
Since addition is commutative, and they have the same mid-point, so they bisect each other.
You might be interested in
h and k are just arbitrarily choosen names for these functions, and (x) is the variable we do all the calculations with
example: (x) can be some function, while d(x)= 2*f(x) always doubles what f(x) would give you. and in order to talk about the new function we give it a new name.
----------------------
let's have a look into it.
and with a look, I mean a look (screenshot 1)
k(x) basically takes the other equation, doubles its values, but also flips the sign (hence -2*h(x)), and then adds 3 (shifting everything 3 units up)
k(x) is a <em><u>vertical stretch</u></em> [note thatthe zero-pounts stay the same] by a factor of <em><u>-2</u></em>, <em><u>translated up</u></em> [you typed translated right twice, but the +3 in the new equation is safely putting everything 3 units higher].
to be honest, I can't get the meaning of some of the blanks and the options you mentioned don't seem to fit well.
I hope I gave you enough insight to do do the quiz anyways.
pls let me no if you solved it or if you need further explanations.
