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Leya [2.2K]
3 years ago
8

A deli is offering two specials. The roast beef special gives a profit of $2.30 per sandwich, whereas the turkey special gives a

profit of $3.10 per sandwich. The roast beef special uses two slices of bread and three slices of cheese. The turkey special uses two slices of bread and four slices of cheese. The deli has 120 slices of bread and 160 slices of cheese available for the specials. The deli wants to maximize its profit selling sandwiches. Let x represent the number of roast beef specials and y represent the number of turkey specials. What are the constraints for the problem?

Mathematics
1 answer:
Sedaia [141]3 years ago
7 0
We put the information above in a table as shown below
The number of bread available is 120, so the first constraint is 
The number of cheese available is 160 slices, so the second constraint is 
The next constraint is the profit 

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Answer:

Value of x = -1 and y = -4

Step-by-step explanation:

BC = 3 (given)

BC = AD ( opposite sides of a parallelogram are equal)

∴ AD = 3

AD = x - y (given)

∴ 3 = x - y

3 + y = x -------- (1)

CD = 2 (given)

CD = AB (opposite sides of a parallelogram are equal)

∴ AB = 2

AB = 2x - y (given)

∴ 2 = 2x - y ----------- (2)

Putting the value of x in (1) To (2)

2 = 2(3+y) - y

2 = 6 + 2y - y

2 = 6 + y

2 - 6 = y

-4 = y

Now, substitute the value of y in (1)

x = 3 + y

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x = 3 - 4

x = -1

Therefore, the value of x = -1 and y = -4.

<u>Cross-checking</u>

2x - y = 2

2*-1 - (-4) = 2

-2 -(-4) = 2

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2 = 2

LHS = RHS

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-1 -(-4) = 3

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3 = 3

LHS = RHS

Thus verified

Hope u understand

Please mark as brainliest

Thank You

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