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Hitman42 [59]
3 years ago
14

NEED AN ANSWER ASAP WILL GIVE BRAINLIEST

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

No, it is not.

Explanation:

A function is a relation in which each element of the domain, or x-value, is mapped to one element of the range, or y-value.

The question we are asked is if cost is a function of the activity type.  This means that cost would be the range and activity type would be the domain.

If this is a function, then each activity type would have only one cost.  However, on different days of the week each activity type has different prices; this means there is more than one cost for each activity type, and it is not a function.

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What is the name of the type of data that a scatterplot is used to analyze? a.univariate data
svet-max [94.6K]

Answer: B

Step-by-step explanation:

The answer is letter b. Bivariate analysis is used to evaluate and analyze bivariate data. It is the simplest form of analysis of exactly two variables, X and Y.It is used to find out the relationship between two sets of values (if there is any). So, the type of data that a scatterplot is used to analyze bivariate data.

4 0
3 years ago
Read 2 more answers
How do I solve this problem?
lesya [120]

Answer:

4x⁻¹

Step-by-step explanation:

4x + 20 25 - x²

_______ ÷ _______ ↷

x² - 5x [x - 5]²

4[x + 5] [-5 + x][5 + x]

_______ ÷ _______

x[x - 5] [x - 5][x - 5]

So what we did here was factor out ALL the Greatest Common Factors [GCFs] in each denominator and numerator, and since we are dividing vertically AND horizontally, according to this, ALL [x - 5] and [x + 5] cancel each other out and all you are left with is this:

4x⁻¹

OR

\frac{4}{x}

This, according to the Negative Exponential Rule [Reverse], is how you rewrite it as a fraction. You bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM POSITIVE TO NEGATIVE:

b⁻ⁿ = 1\bⁿ

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

4 0
3 years ago
-1.2= y/2.4 -1.7<br> Solve for y
evablogger [386]

{\huge{\boxed{\sf{Question}}

-1.2= y\div2.4 -1.7

Solve for y

{\huge{\boxed{\sf{Answer\:with\:explanation }}}

let's put our equation first

-1.2= y\div2.4 -1.7

Flip the equation

y\div2.4-1.7=-1.2

Now follow the rule of BOMDAS/PEMDAS

{\huge{\boxed{\sf{BOMDAS }}}

  • Brackets
  • Of multiplication
  • Division
  • Addition
  • Subtraction

{\huge{\boxed{\sf{PEMDAS}}}

  • Parenthesis
  • Exponents
  • Multiplication
  • Division
  • Addition
  • Subtraction

_________________________

{\huge{\boxed{\sf{Solve\:the\:equation}}}

_________________________

y\div2.4-1.7=-1.2

{\underline{simplify}}

0.416667y-1.7=-1.2

add 1.7 to both sides

0.416667y=0.5

Divide both sides by 0.416667

y=1.2

{\huge{\boxed{\sf{Answer}}}

y would equal 1.2

4 0
3 years ago
-4(3s)+2 (-t); for s = 1/2, t = -3<br>please help me
kumpel [21]
Hi there. :)

I'll try to make this simpler for you.

Let's focus on the equation from left to right, to avoid clutter.

-4(3 * 1/2) = -4(1.5)

Now to the right.

+ 2(3) = + 6

Now combine!

-4(1.5) + 6 = 

-6 + 6 = 0

The answer is 0.
7 0
4 years ago
The pressure, P (in lbs/ft2 ), in a pipe varies over time. Five times an hour, the pressure oscillates from a low of 90 to a hig
Lunna [17]

P=160-70*cos(2π*(1/12)*t)

• Pressure in mathematics or physics is defined as force per unit area. The pressure exerted by a solid object which is resting on top of a solid surface is the weight divided by the area of the object . SI unit of force is Newton (N).

First, we find the amplitude by taking the difference between the peak values and dividing by two:

Amplitude=(230+90)/2=70

We can find the center value by either adding 70 to the minimum or subtracting 70 from the maximum:

90+70=160

230-70=160

This tells us that the Center Value=160

The frequency that we are operating at is given as:

f = 5/hour

so in minutes

f=5*(1/60)/minute=5/60=1/12 per minute

So, combining everything we get

P=160-70*cos(2π*(1/12)*t)

Learn more about Pressure here

brainly.com/question/26040104

#SPJ9

7 0
2 years ago
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