Which of the following is the best estimate for checking the given problem

Need help this is on acellus

madam [21]

The complete inequality is -2 < x < 35

<h3>How to determine the range of value of x?</h3>

The figure attached to the question is the given parameter

From the figure, we understand that:

Side length BA and side length BD are equal.

This is represented as:

BA = BD

Because the side length AC is less than the side length CD, then it means that:

The measure of the angle ABC is less than the measure of the angle CBD

This is represented as:

∠ABC < ∠CBD

Where

ABC = x + 2

and

CBD = 37

Substitute ABC = x + 2 and CBD = 37 in the inequality expression ∠ABC < ∠CBD

So, we have:

x + 2 < 37

Subtract 2 from both sides of the inequality

x + 2 - 2 < 37 - 2

Evaluate the differences

x < 35

From the question, we have the following incomplete inequality

-2 < x < [ ]

Complete the inequality as follows:

-2 < x < 35

Hence, the complete inequality is -2 < x < 35

Read more about angles at:

brainly.com/question/24839702

#SPJ1

8 0

2 years ago

Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$

Therefore:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30$

8 0

4 years ago

Read 2 more answers

Select all the correct equations.

Naya [18.7K]

Answer:

You did not post the options, but i will try to answer this in a general way.

Because we have two solutions, i know that we are talking about quadratic equations, of the form of:

0 = a*x^2 + b*x + c.

There are two easy ways to see if the solutions of this equation are real or not.

1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).

2) look at the determinant.

The determinant of a quadratic equation is:

D = b^2 - 4*a*c.

if D > 0, we have two real solutions.

if D = 0, we have one real solution (or two real solutions that are equal)

if D < 0, we have two complex solutions.

3 0

3 years ago

Pleaseeee! <br>I need help evaluating this:<br><br><br>Tan 2 theta-(1-tan^ 2 )=?

andreev551 [17]

Answer:

$\tan \left(2\theta\right)-1+\tan ^2\left(\theta\right)$

Key:

• $-\left(a-b\right)=-a+b$

Step-by-step explanation:

$\tan \left(2\theta\right)-\left(1-\tan ^2\left(\theta\right)\right)$

$-\left(1-\tan ^2\left(\theta\right)\right)=-1+\tan ^2\left(\theta\right)$

$=\tan \left(2\theta\right)-1+\tan ^2\left(\theta\right)$

7 0

2 years ago

Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB

vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

$\frac{LB}{CL}= \frac{AB}{AC}$