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2 years ago

Can someone help me this problem

Mathematics

1 answer:

konstantin123 [22]2 years ago

8 0

Answer:

A) Yes, m=-3 and b = -3

Step-by-step explanation:

The m is the slope of the line and the b is the y-intercept. We can see that the y-intercept is at -3, so that means D and B are not the answer. This leaves us with A and C. The slope of the line is going down instead of up, meaning that the slope of the line is negative. This means that C is not the answer.

Therefore, the answer is A, m= -3 and b= -3.

You might be interested in

A number x divided by -1 is at least -4

Vinil7 [7]

A number x divided by -1 is at least -4.

x / -1 ≥ -4

Multiply both sides by -1.

x ≤ 4

Remember, when multiplying or dividing by a negative, you must change the sign's direction.

~Hope I helped!~

7 0

3 years ago

Which list includes the lower extreme, the lower quartile, the median, the upper quartile, and the upper extreme for the data se

PtichkaEL [24]

Lower extreme- 8
Lower quartile- 20
Median- 30
Upper quartile- 35
Upper extreme- 42

Hope this helps!

7 0

2 years ago

A can of soda is placed inside a cooler. As the soda cools, its temperature T (x) in degrees celsius is givien by the following

wel

Answer:

Initial 18 degrees Celsius

After 20 minutes, 5 degrees Celsius

Step-by-step explanation:

It’s initial temperature can be calculated as at the time when x = 0

When x = 0, the temperature is -6+24 = 18 degrees Celsius

This is because the exponent part equals 1 since anything raised in to the power of zero is one.

After twenty minutes,

T(x) = -6 +24e^-0.038(20)

T(x) = -6 + 11.224 = 5.224

And that is approximately 5 degrees Celsius to the nearest degree

8 0

3 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago

Complete the following statements.

Charra [1.4K]

Answer:

1.) ax^2 + bx+ c =0

2.) parabola

3.) X=-b2a

4.) maximum

5.) minimum

Step-by-step explanation: hope this helps

4 0

3 years ago