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Aleksandr-060686 [28]
2 years ago
11

Can someone help me this problem

Mathematics
1 answer:
konstantin123 [22]2 years ago
8 0

Answer:

A) Yes, m=-3 and b = -3

Step-by-step explanation:

The m is the slope of the line and the b is the y-intercept. We can see that the y-intercept is at -3, so that means D and B are not the answer. This leaves us with A and C. The slope of the line is going down instead of up, meaning that the slope of the line is negative. This means that C is not the answer.

Therefore, the answer is A, m= -3 and b= -3.

You might be interested in
A number x divided by -1 is at least -4
Vinil7 [7]
A number x divided by -1 is at least -4.

x / -1 ≥ -4

Multiply both sides by -1.

x ≤ 4

Remember, when multiplying or dividing by a negative, you must change the sign's direction.

~Hope I helped!~
7 0
3 years ago
Which list includes the lower extreme, the lower quartile, the median, the upper quartile, and the upper extreme for the data se
PtichkaEL [24]
Lower extreme- 8
Lower quartile- 20
Median- 30
Upper quartile- 35
Upper extreme- 42

Hope this helps!
7 0
2 years ago
A can of soda is placed inside a cooler. As the soda cools, its temperature T (x) in degrees celsius is givien by the following
wel

Answer:

Initial 18 degrees Celsius

After 20 minutes, 5 degrees Celsius

Step-by-step explanation:

It’s initial temperature can be calculated as at the time when x = 0

When x = 0, the temperature is -6+24 = 18 degrees Celsius

This is because the exponent part equals 1 since anything raised in to the power of zero is one.

After twenty minutes,

T(x) = -6 +24e^-0.038(20)

T(x) = -6 + 11.224 = 5.224

And that is approximately 5 degrees Celsius to the nearest degree

8 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Complete the following statements.
Charra [1.4K]

Answer:

1.) ax^2 + bx+ c =0

2.) parabola

3.) X=-b2a

4.) maximum

5.) minimum

Step-by-step explanation: hope this helps

4 0
3 years ago
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