9514 1404 393
Answer:
a. plane DEA
Step-by-step explanation:
A plane can be named by naming any 3 non-collinear points in the plane, or by using the plane's name as indicated in the drawing.
Here, points in the plane are A, D, E, F, with DEF all on the same line. So A plus any two points from the line will constitute a name for the plane. Also, this plane is identified with a script M that can be used to name the plane.
M is not an answer choice, but DEA is. So, the appropriate choice is ...
plane DEA
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F is a point, not a plane name. C is not on the plane, so cannot be used to name it. 'k' is a line name, not a plane name.
Y= 3/5x - 15/5
This should be your answer
75,88,90,96,98,100
minimum = 75
Q1 = 88.....this is where the box begins
Q2 (the median) = (90 + 96) / 2 = 186/2 = 93....this is the line in the box
Q3 = 98....this is where the box ends
maximum = 100
88_93______98
75_______| | |___100
|___|_______|
It is C trust me I’m doing the same thing
Answer:
f(x) = -4/3x² -2/3x +10
Step-by-step explanation:
The quadratic regression function of a graphing calculator or spreadsheet can determine the equation for you.
___
Or, you can determine it yourself.
The equation can be written in the form ...
f(x) = a(x +3)(x -5/2) . . . . . . . using the given x-intercepts
for some value of "a"
For x = 0, this must match the y-intercept.
f(0) = a(0 +3)(0 -5/2) = 10
-15/2·a = 10
a = -20/15 = -4/3
So, the function can be written as ...
f(x) = (-4/3)(x +3)(x -5/2)
or
f(x) = -4/3x² -2/3x +10
