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2 years ago

What is the equation of the line that passes through the point (-5,0) and has a

Mathematics

2 answers:

Agata [3.3K]2 years ago

5 0

The top person is incorrect your answer is

Equation: y=3/5x+3

algol [13]2 years ago

4 0

Y= 3/5x - 15/5
This should be your answer

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The following graph shows the distance Thomas is from his home (in meters) for a period of 2 minutes. Determine the average rate

irga5000 [103]

The answer:
the average rate of change for the first 50 seconds:
it is v= 100 m/ 50 s = 2 m/s
Thomas speed is 2 m in each second for the first 50 seconds.

The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s

6 0

3 years ago

a jar of pinto beans and black beans in a ratio of 1:1,and 300 of the beans are in pinto beans. How many beans in total are ther

garik1379 [7]

I believe the answer would be 600

3 0

3 years ago

Read 2 more answers

Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1)

ioda

(1) Looks like the joint density is

$f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0$

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

$\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1$

$\implies\boxed{c=\dfrac1{32}}$

(2) The region in which X > 2 and Y < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

$P(X>2,Y$

(3) Are you supposed to find the marginal density of X, or the conditional density of X given Y?

In the first case, you simply integrate the joint density with respect to y:

$f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0$

In the second case, we instead first find the marginal density of Y:

$f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0$

Then use the marginal density to compute the conditional density of X given Y:

$f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y$

6 0

3 years ago

What is 7 1/5 - 6 2/5

Artist 52 [7]

Answer:

I think , the answer is 9/5 or 1.8 in decimal

3 0

3 years ago

How do you solve 4b^2+8b+7=4 using the quadratic formula

lina2011 [118]

$
4b^2+8b+7=4\\
4b^2+8b+3=0\\\\
x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\
x=\dfrac{-8\pm\sqrt{8^2-4\cdot4\cdot3}}{2\cdot4}\\
x=\dfrac{-8\pm\sqrt{64-48}}{8}\\
x=\dfrac{-8\pm\sqrt{16}}{8}\\
x=\dfrac{-8\pm4}{8}\\
x=\dfrac{-2\pm1}{2}\\
x=\dfrac{-1}{2 }\vee x=\dfrac{-3}{2}\\
x=-\dfrac{1}{2 }\vee x=-\dfrac{3}{2}$

4 0

3 years ago

Read 2 more answers