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3 years ago

Plz plz plz plz plz plz help me

Mathematics

2 answers:

svlad2 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Girl i wanna tltlk with you and i am a girl too

sladkih [1.3K]3 years ago

3 0

Answer:

a)1

b)3

c)0

d)2

Step-by-step explanation:

to find the degree of the polynomial just look at the exponents. The highest exponent you see is the answer. For polynomials with variable but no exponents (like in a) the degree is technically 1 for that expression. if there is just a digit with no exponent (like in c) then the degree is 0

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Difficukt question help

Zigmanuir [339]

Well, if two burgers and one hotdog costs 4.82, and one burger and two hotdogs cost 3.70, you substract those to find the cost of one burger. Then you add that by two, and that's the cost of two burgers. Now you just need the cost of two hotdogs. Subtract the cost of two burgers and 4.82. Then divide that by two. That's answer!

6 0

4 years ago

At most, Bob can spend $50 on sandwiches and chips for his picnic. He already bought chips for six dollars and will buy sandwich

arlik [135]

50 - 6 = 44

44 / 4.50 = 9.77777778 ( 9 sandwich cuz u can get 0.77777778 of a sandwich.)

He can buy 9

3 0

3 years ago

Solve the Differential equation 2(y-4x^2) dx + x dy = 0

padilas [110]

Assume a solution of the form $\Psi(x,y)=C$ . Taking the differential of both sides would give the ODE

$\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0$

where $\Psi_x=2y-8x^2$ and $\Psi_y=x$ . The ODE is exact if $\Psi_{xy}=\Psi_{yx}$ . We have

$\Psi_{xy}=(2y-8x^2)_y=2$

$\Psi_{yx}=(x)_x=1$

so the ODE is not exact. However, multiplying both sides by $x$ gives

$(2xy-8x^3)\,\mathrm dx+x^2\,\mathrm dy=0$

and now

$(x\Psi_x)_y=(2xy-8x^3)_y=2x$

$(x\Psi_y)_x=(x^2)_x=2x$

so the ODE is now exact.

Now,

$\Psi_x=2xy-8x^3\implies \Psi(x,y)=x^2y-2x^4+f(y)$

$\Psi_y=x^2=x^2+f_y\implies f_y=0\implies f(y)=C$

So the ODE has solution

$\Psi(x,y)=x^2y-2x^4+C=C$

or simply

$\boxed{x^2y-2x^4=C}$

3 0

4 years ago

George has a triangle-shaped garden in his backyard. He drew a model of this garden on a coordinate grid with vertices A(4, 2),

oksian1 [2.3K]

Given:

Vertices of a triangular garden:

A(4,2)
B(2,4)
C(6,4)
Scale factor = 0.5

Find the distance between points:

d = √(x2-x1)^2 + (y2-y1)^2

dAB = 2√2
dBC = 4
dCA = 2√2

A similarly shaped garden is to be created using the scale factor, 0.5:

A' = 2√2 / 0.5 = 4√2
B' = 4 / 0.5 = 8
C' = 2√2 / 0.5 = 4√2

6 0

3 years ago

√35 + √30 is approximately

andrezito [222]

Answer:

about 11

Step-by-step explanation:

answer is in picture

7 0

3 years ago

Plz plz plz plz plz plz help me ​

Plz plz plz plz plz plz help me