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Naddik [55]
3 years ago
10

Let f(x)=-2x-3 and g(x)=x2+5x Find f(-4) - g(1)

Mathematics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

1

Step-by-step explanation:

f(x) = -2x - 3

f(-4) = -2(-4) - 3

=8 - 3

=5

g(x) = x² + 5x

g(1) = 1² + 5(1)

=1 + 5

=6

=f(-4) - g(1)

=5-6

=-1

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At time t>=0, the acceleration of a particle moving on the x-axis is a(t)=t+sin(t). At t=0, the velocity of the particle is -
Rufina [12.5K]

Answer:

The velocity of the particle will be zero for  t = 1.47 sec .

Step-by-step explanation:

Given equation:

                                           a(t)=t+sin(t)

lets integrate it with respect to time,

                                           ∫ a(t) dt = ∫(t+sin(t)) dt

                                      ⇒ v(t) = \frac{t^{2} }{2} - cos(t) +c

At, t=0, v= -2 so,

                                     ⇒ -2 = 0 - 1 +c

                                     ⇒ c= -1

Hence,

                                     v(t) = \frac{t^{2} }{2} - cos(t) -1

for the velocity to be zero,

                                     0 =  \frac{t^{2} }{2} - cos(t) -1

                                ⇒  t = 1.47 sec (taking only positive value)

So at 1.47 sec the velocity of particle will be zero.

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Answer:

Step-by-step explanation:

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7 0
3 years ago
Is my answer correct?
scZoUnD [109]

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