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serious [3.7K]
3 years ago
7

Determine whether the given binomial is a factor of

Mathematics
1 answer:
Gwar [14]3 years ago
4 0

Answer:

Use the Factor Theorem to determine if the given binomial is a factor of the given polynomial function: f(x)=2x3+x2-5x+2; x+2 a. f(-2)=0; yes, the binomial ...

Step-by-step explanation:

so the answer is f(x)=0

This is my answer

PLEASE MARK ME AS BRAINLIEST

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Order the values from smallest (top) to largest (bottom) 1. 5 2/3 2. 5 1/6 3. 4 5/6 4. 4 1/2 5. 4 1/3 6. 5 6/6
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4 1/3, 4 1/2, 4 5/6, 5 1/6, 5 2/3, 5 6/6
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Solve the equation<br><br> 9<br> - =18<br> X
BaLLatris [955]

Answer:

x=-0.5

Step-by-step explanation:

the question is -9=18x

we divide both sides by 9

-1=2x

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8 0
3 years ago
An oil drilling company ventures into various locations, and its success or failure is independent from one location to another.
densk [106]

Answer:

a) 18.77% probability that the driller drills at 10 locations and has 1 success

b) 75.60% probability that the driller drills at 10 locations and has at least 2 success

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a success, or it is not. The probability of a drill being a success is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

10 locations

This means that n = 10

Suppose the probability of a success at any specific location is 0.25.

This means that p = 0.25

(a) What is the probability that the driller drills at 10 locations and has 1 success?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.25)^{1}.(0.75)^{9} = 0.1877

18.77% probability that the driller drills at 10 locations and has 1 success

(b) What is the probability that the driller drills at 10 locations and has at least 2 success?

Either there are less than 2 success, or there are at least 2. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.25)^{0}.(0.75)^{10} = 0.0563

P(X = 1) = C_{10,1}.(0.25)^{1}.(0.75)^{9} = 0.1877

P(X < 2) = P(X = 0) + P(X = 1) = 0.0563 + 0.1877 = 0.2440

P(X < 2) = P(X = 0) + P(X = 1) = 1 - 0.244 = 0.756

75.60% probability that the driller drills at 10 locations and has at least 2 success

8 0
3 years ago
F(x) = x2 + 12x +32<br><br> Find the roots of the function
Svet_ta [14]

Answer: Evaluate

Step-by-step explanation:

4 0
3 years ago
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