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Leona [35]
3 years ago
6

6q + 9 ≤ 9 and 6q + 9 ≥ −9

Mathematics
2 answers:
Ilya [14]3 years ago
7 0
Hello there!

6q + 9 ≤ 9

Start by subtracting 9 from both sides

6q + 9 - 9 ≤ 9 - 9

6q ≤ 0

Then divide both sides by 6

6q/6 ≤ 0/6

q ≤ 0

--------------

The second equation
6q + 9 ≥ -9

Start by subtracting 9 from both sides

6q + 9  - 9 ≥ -9 - 9

6q ≥ -18

Divide both sides by 6

6q/6 ≥ -18/6

q ≥ -3


Good luck with your studies!
kenny6666 [7]3 years ago
4 0
If you combine both of these inequalities, you will get 
-9 ≤ 6q + 9 ≤ 9

You can further simplify this be using the absolute value.
If you use the absolute value, you will get
| 6q + 9 | ≤ 9

If you're trying to solve for q, use
-9 ≤ 6q + 9 ≤ 9
Subtract all parts by 9
- 18 ≤ 6q ≤ 0
Divide all parts by 6
- 3 ≤ q ≤ 0

Have an awesome day! :)
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The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.

<h3>What is Area ?</h3>

Area is the space occupied by a two dimensional object,

The area and perimeter of the given shape can be determined by dividing it into basic shapes.

The area and the perimeter of the shape given = Area of the rectangle +Area of upper triangle - Area of two small triangles at the bottom

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Area of small Triangle = (1/2) * 3*6 = 9 sq.mi

Area of other small Triangle = (1/2)*3*3 = 9/2 sq.mi

Area of the figure = 45 +13.5 -9-4.5

Area of the figure =  45 sq.mi

Similarly for Perimeter = Perimeter of the rectangle +Perimeter of upper triangle -Perimeter of two small triangles at the bottom

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