The nth term of the sequence is 2n - 8
<h3>Equation of a function</h3>
The nth term of an arithmetic progression is expressed as;
Tn = a + (n - 1)d
where
a is the first term
d is the common difference
n is the number of terms
Given the following parameters
a = f(1)=−6
f(2) = −4
Determine the common difference
d = f(2) - f(1)
d = -4 - (-6)
d = -4 + 6
d = 2
Determine the nth term of the sequence
Tn = -6 + (n -1)(2)
Tn = -6+2n-2
Tn = 2n - 8
Hence the nth term of the sequence is 2n - 8
Learn more on nth term of an AP here: brainly.com/question/19296260
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Answer:
A
Step-by-step explanation:
The student must have thought that every single arrowhead is a line of symmetry, so since there are 10 arrowheads, there must be 10 lines of symmetry. This is incorrect because if you look closely at the diagram, each line has 2 arrowheads, so the student is overcounting by a factor of 2. They should have just counted the number of lines, not arrowheads. Therefore, there must be 10/2 = 5 lines of symmetry, not 10. Hope this helps!
Step-by-step explanation:
what is to be done ? just that addition ?
first, let's all bring to pure fractions.
7 2/3 = (7×3 + 2)/3 = 23/3
2 1/5 = (2×5 + 1)/5 = 11/5
then let's bring all to a common denominator (bottom part of the fraction).
for this, we need to find the first (or any) common multiple of the 2 denominators (here 3 and 5).
if you have no other idea, just multiply them with each other (in our case here this is also the smallest common multiple) : 3×5 = 15.
so, we bring both fractions into the form of .../15. then it is easy to add them.
23/3 = x/15
x = 23/3 × 15 = 23×15/3 = 23×5 = 115
=>
23/3 = 115/15
11/5 = x/15
x = 11/5 × 15 = 11×15/5 = 11×3 = 33
=>
11/5 = 33/15
now the addition :
115/15 + 33/15 = 148/15 or 9 13/15
this is the result, as it cannot be further simplified.
First cross-multiply 48×2= 96
Next do 96÷3= 32
So the answer should be 32.
