Answer:
B
Explanation:
When you initialize an instance of FunEvent(tags, year) and assign it to bc. The instance variables in this case are: self.tags = ["g", "ml"] and self.year = 2022. But then you alter tags, which will also change self.tags, since self.tags is a reference to the list you passed in as an argument. This is not the case when you do year=2023 because, first of all, integers are not mutable, and also because even if somehow integers were mutable, you're not changing the object in-place, you're simply changing the where the "variable" is pointing to. So for example if you did tags = ["g", "ml", "bc"] instead of tags.append("bc"), it would also not change the value of the instance variable "tags", because you wouldn't be changing the object in-place. So when you print(bc), the instance variables will be ["g", "ml", "bc"] and 2022. When you try to print an object, it call try to convert it into a string using the __str__ magic method. In this case it will return a string formatted as "Event(tags={self.tags}, year={self.year}) which will output "Event(tags=['g', 'ml', 'bc'], year=2022)" So the correct answer is B
the checked bounced because he didn’t have any money.
mark me brainliest please!!!!!
Answer:
randint
Explanation:
Just did my quiz and got a 100%
Answer:
I wrote this myself, it should be working. I think this is what the instructions were looking for.
The code below should return
Squared: 1296
Mod: 0
Quadrupled: 16
Explanation:
def threeParams(squared, mod, quadruples):
array = [squared, mod, quadruples]
array[0] = squared ** 2
array[1] = mod % 5
array[2] = quadruples * 4
return array
valueArr = threeParams(36, 15, 4)
print(f"Squared: {valueArr[0]}\nMod: {valueArr[1]}\nQuadrupled: {valueArr[2]}")
