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HACTEHA [7]
3 years ago
12

A farmer has a house at the point (0, 0). He has a corn field that can be found by driving 2 units left, 2 units up, and 4 units

right. If he instead walks diagonally to his corn field, how far has he gone? Round to 2 decimal places.
Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

The answer should be 73.97

ikadub [295]3 years ago
4 0

Answer:

The answer should be 73.97

Step-by-step explanation:

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Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
3 years ago
Solve for x. 5x+9=24
OlgaM077 [116]

Answer:

5x = 24 - 9 \\ 5x = 15 \\ x =  \frac{15}{5}  \\ x = 3

6 0
3 years ago
Read 2 more answers
How do I answer the question?
Sholpan [36]
Its b hope it helps good luck
5 0
3 years ago
I don't know how to do this. Please help. Ty! :)
Naya [18.7K]

Step-by-step explanation:

A U B means all values containing in A and B.

Therefore A U B = {3,6,7,11,12,15} (C)

4 0
3 years ago
the SAT was recently given at mcdowell high school. joe scored a 288 on a math section which is 2 standard deviations below the
vichka [17]
Let \mu be the mean and \sigma the standard deviation.

Joe's score tells you that \dfrac{288-\mu}\sigma=-2, while Jon's score says \dfrac{633-\mu}\sigma=1. Solve this to get \mu=518 and \sigma=115.
8 0
3 years ago
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