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Bess [88]
2 years ago
6

A wire 4 1/2 feet long is being cut into smaller pieces of wire, each. 1 1/4 ft long what is the max number of smaller pieces of

wire that can be cut from the original piece of wire?
Mathematics
2 answers:
ivolga24 [154]2 years ago
3 0

4.5 divided by 1.25 is 3.6

for peices in total it is 4.

for peices the right length it is 3

spayn [35]2 years ago
3 0

Answer:

4.5 / 1.25 = 3.6 so 3 pieces can be cut

Step-by-step explanation:

you need to take 4 1/2 and divide it by 1 1/4 to get the number of pieces that can be cut. Since it its not a whole number you need to round it to 3

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What is the equation of the line in point-slope form?
evablogger [386]

Answer:

y +500 = -\frac{1}{5}(x - 100)

Step-by-step explanation:

Given

The attached graph

Required

Determine the equation in point slope form

From the graph, we have the following points;

(x_1,y_1) = (-400,-400)

(x_2,y_2) = (100,-500)

First, we calculate the slope (m):

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{-500 - (-400)}{100- (-400)}

m = \frac{-500 +400}{100+400}

m = \frac{-100}{500}

m = -\frac{1}{5}

The equation is then calculated using:

y - y_2 = m(x - x_2)

Substitute x and y values

y - (-500) = -\frac{1}{5}(x - (100))

y +500 = -\frac{1}{5}(x - 100)

8 0
2 years ago
The population density of New York City is 26,403 people per square mile. If 12,383,007 people live in New York City, what is th
sergejj [24]
469 miles squared is the answer
3 0
3 years ago
Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.
Kamila [148]

Answer:

Step-by-step explanation:

<em>Let x be time, in semesters, remaining before Manuel graduates</em>.  We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1.  <u>x semesters remaining:  fees</u>

  Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2.  <u>x semesters remaining:  tuition</u>

  Remaining cost, y, is the product of the tuition (times the number of semesters, x.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3.  <u>x semesters remaining:  tuition and fees</u>

  Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0
1 year ago
A number d minus is less than -1
katrin [286]

\boxed{d-4

<h2>Explanation:</h2>

Hello! Recall you need to write complete questions in order to find exact answers. So in this problem I'll assume the question is:

<em>A number d minus 4 is less than -1</em>

<em />

So it is easy to know that we need to write an inequality here because of the words "less than", which implies that we must use the symbol <. So let's solve this step by step.

Step 1. A number d minus 4.

This statement includes the word "minus", so we need to use the symbol (-). Therefore:

d-4

Step 2. A number d minus 4 is less than

As we said above, here we need to use the symbol (<). So:

d-4

Step 3. A number d minus 4 is less than -1

Finally, we get:

d-4

<h2>Learn more:</h2>

Inequalities: brainly.com/question/9611462

#LearnWithBrainly

3 0
2 years ago
Which set of numbers could be the length of the sides
Svetllana [295]

Answer: Choice C)  {6, 9, 12}

=======================================================

Explanation:

Something like choice A can't form a triangle because the first two sides add to 6+9 = 15, which is <u>not</u> longer than the third side 15. We need to have x+y > z to be true. The same goes for choice B as well because 3+3 = 6 is too small compared to the third side 7. Choice D is similar to choice A.

In short, we can rule out choices A, B, and D.

The only thing left is choice C. Picking any two sides leads to having that sum be larger than the third side

  • 6+9 = 15 which is larger than 12
  • 9+15 = 24 which is larger than 6
  • 6+15 = 21 which is larger than 9

So the conditions of the triangle inequality theorem work out here, and we have a triangle.

3 0
3 years ago
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