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2 years ago

What is the value of 7742

Mathematics

1 answer:

marta [7]2 years ago

7 0

Answer:

7=thousands

7=hundreds

4=tens

2=ones

Hope this helps

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What is the value of 4 in the number 358.547? A) 0.0004 B) 0.004 C) 0.04 D) 4

LiRa [457]

The answer is C) 0.04 becuase the 4 is in the hundredths place

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2 years ago

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A medical researcher needs 37 people to test the effectiveness of an experimental drug. If 101 people have volunteered for the t

Rashid [163]

Answer:

The number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\cdot (n-k)!}$

Compute the number of ways to select 37 people from 101 as follows:

${101\choose 37}=\frac{101!}{37!\cdot (101-37)!}$

$=\frac{101!}{37!\times 64!}\\\\=\frac{101\times 100\times 99\times....64!}{37!\times 64!}\\\\=5397234129638871133346507775$

Thus, the number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

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2 years ago

THIS IS FOR THE SAME TEST IF YOU WANT TO HELP ILL GIVE 50 POINTS

katrin2010 [14]

Answer: 0.5%

3 pages out of 650 is 0.5%

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2 years ago

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Determlne the circumference of a circle with a radius of 8 meters.

ollegr [7]

Answer:

The first one

Step-by-step explanation:

answer = 50.2

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3 years ago

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Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo

pav-90 [236]

Answer:

Probability distribution vector = $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$

Step-By-Step Explanation

If $P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)$ is the transition matrix for a Markov chain with two states.

$x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)$ be the initial state vector for the population.

$X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)$

$X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)$

In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

This is called the steady-state (or limiting,) distribution vector.

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2 years ago