D. 36 - just do the reverse of the question, (-12 * 3 = ...)
Answer: The transformation <u>sin(x)-7</u> results in a vertical shift down.
The transformation <u>sin(x+7)</u> results in a horizontal shift left.
The transformation <u>sin(x)+7</u> results in a vertical shift up.
The transformation <u>sin(x-7)</u> results in a horizontal shift right.
Step-by-step explanation:
Transformation:
If f(x) is a function then
f(x)+k is a vertical shift k units upwards.
f(x)-k is vertical shift k units downwards.
f(x-h) is horizontal shift h units rightwards.
f(x+h) is horizontal shift h units leftwards.
So,
The transformation <u>sin(x)-7</u> results in a vertical shift down.
The transformation <u>sin(x+7)</u> results in a horizontal shift left.
The transformation <u>sin(x)+7</u> results in a vertical shift up.
The transformation <u>sin(x-7)</u> results in a horizontal shift right.
Answer:
<h2>hope it helps you see the attachment for further information ✌✌✌✌✌✌✌</h2>
Answer:
144 sq in
Step-by-step explanation:
Face height=9, bases=6 in
#Assume the pyramid has a square base.
First we need to calculate the perpendicular height of the pyramid:
![#Pythagorean \ Theorem\\a^2+b^2=c^2\\9^2-(0.5\times 6)^2=h^2\\72=h^2\\h=\sqrt{72} \ in](https://tex.z-dn.net/?f=%23Pythagorean%20%5C%20Theorem%5C%5Ca%5E2%2Bb%5E2%3Dc%5E2%5C%5C9%5E2-%280.5%5Ctimes%206%29%5E2%3Dh%5E2%5C%5C72%3Dh%5E2%5C%5Ch%3D%5Csqrt%7B72%7D%20%5C%20in)
Now to find the surface area of each pyramid:
![A=lw+l\sqrt{(w/2)^2+h^2}+w\sqrt{(l/w)^2+h^2}\\\\\#w=l=6,h=\sqrt{72}\\\\A=6^2+6\sqrt{(6/2)^2+72}+6\sqrt{(6/6)^2+72}\\\\A\approx 144\ sq \ in](https://tex.z-dn.net/?f=A%3Dlw%2Bl%5Csqrt%7B%28w%2F2%29%5E2%2Bh%5E2%7D%2Bw%5Csqrt%7B%28l%2Fw%29%5E2%2Bh%5E2%7D%5C%5C%5C%5C%5C%23w%3Dl%3D6%2Ch%3D%5Csqrt%7B72%7D%5C%5C%5C%5CA%3D6%5E2%2B6%5Csqrt%7B%286%2F2%29%5E2%2B72%7D%2B6%5Csqrt%7B%286%2F6%29%5E2%2B72%7D%5C%5C%5C%5CA%5Capprox%20144%5C%20sq%20%5C%20in)
Hence amount of construction paper needed to make each pyramid is 144 sq in
Answer:
2w + 3x ≤ 36
Step-by-step explanation:
Given that :
Hours needed to paint wall = 2 hours
Hours required to frame window = 3 hours
Total hours to spend ≤ 36
Let :
Number of walls to paint = w
Number of windows to frame = x
Hence,
Hours required to paint a wall * number of waas to paint) + (hours required to frame a window * Number of windows to frame.)
(2*w) + (3*x) ≤ 36
2w + 3x ≤ 36