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Vlad1618 [11]
2 years ago
5

t="\sqrt{x} +2\sqrt{x}-1=2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

=> 3\sqrt{x} =3

=>\sqrt{x} =1

=> x = 1 and x= -1

Step-by-step explanation:

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If 6!+7!+8!=(n)(6!), then the value of n is<br> A) 15<br> B)16<br> C)63<br> D)64<br> E)15!
gladu [14]
6!+7!+8!=(n)(6!)
calculate the individual values first:
6!=720
7!=5040
8!=40320

plug them into the equation:
720+5040+40320=n720
solve for n
5760+40320=n720
46080=n720
divide both sides by 720 to isolate n
46080/720=n720/720
64=n
6 0
3 years ago
Which value of b would make x²+bx-30 factorable?<br> A. -31<br> B. -17<br> C. 11<br> D. 13
dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b±\sqrt{b^{2}-4ac} /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since \sqrt{13^{2}-4*1*(-30) = \sqrt{289} = 17. So b=13.

5 0
4 years ago
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Stells [14]

Answer:

Step-by-step explanation:

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Hope this helps :)

8 0
3 years ago
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vodomira [7]
Answer:

11/9

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Plzzzz help will give brainliest needs to be done my 11:30 plzz will fail in not answered by that time
navik [9.2K]

(c/ b * 0) is just (c/0) and you cannot divide by 0

3 0
3 years ago
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